Adding integers
A lift three floors below the street goes up seven floors. Where does it stop, and how do you add two numbers that pull in opposite directions?
Where you are 2 in Adding and subtracting integers
When you reach for it
Many quantities come with a direction. A temperature can be above zero or below it, a game score can be points ahead or points behind, a floor can be above the street or below it. The Integers record both the size and the direction in one number: 5 for five above, -5 for five below. As soon as two of these quantities are combined, you need to add integers.
When both numbers point the same way, adding them is the addition you already know, with a sign attached. The new case is when they point opposite ways. A lift going up 7 floors from level -3, a player on -27 points who wins a hand worth 50, a cave explorer at -90 meters who climbs 35 meters: in each one, the second number partly undoes the first. The sum is what is left after the two cancel as far as they can.
This lesson takes three days. Part 1 reads a sum as a move along the number line. Part 2 shows the same sums with counters, where the canceling can be seen as pairs that are worth nothing. Part 3 turns both pictures into a way of adding any integers without drawing, using absolute value, and uses it on sums of several numbers, expressions and problems.
The procedure
Part 1: adding as moves on the number line
Read an integer as a move along the number line. A positive number is a move to the right, a negative number a move to the left, and the size of the number, its absolute value, is how far the move goes. So +4 means “four to the right” and -4 means “four to the left”.
To add a + b, start at a and make the move b. The point where you land is the sum. This is exactly what addition meant before negative numbers: 2 + 3 was “start at 2 and go 3 to the right”. The only new thing is that a move can now go left.
The three lines in the figure show the three ways a sum can go.
- -1 + (-4): start at -1 and move 4 to the left. The start and the move point the same way, so the sum is farther from zero than either: -5.
- 3 + (-7): start at 3 and move 7 to the left. The first 3 steps bring you back to 0, and the other 4 carry you past it to -4.
- -5 + 8: start at -5 and move 8 to the right. Five steps reach 0, and 3 more land on 3.
Two special moves are worth naming. Adding 0 is a move of no length, so a + 0 = a. And adding the opposite of a number, the same distance on the other side of zero, always lands on 0: starting at 6 and moving 6 to the left lands on 0. For every integer a,
When a negative number follows a plus sign, it is written in brackets, 3 + (-7), so that the two signs do not run together. The bracket changes nothing about the value.
Part 2: adding with counters
A second picture makes the canceling visible. Let a white counter marked + stand for 1 and a shaded counter marked - stand for -1. Any integer can be shown by a pile of counters: 4 is four white counters, -6 is six shaded ones.
One white counter and one shaded counter together are worth 1 + (-1) = 0. Such a pair is a zero pair, and it is the counter version of a + (-a) = 0. Since a zero pair is worth nothing, it can be removed from a pile, or added to one, without changing what the pile is worth.
To add two integers, put both piles together and count what they are worth.
- Same signs. All the counters are the same color, so there are no zero pairs. Count them all: -3 + (-2) is five shaded counters, worth -5.
- Different signs. Line the two colors up against each other and ring each zero pair. The pairing stops when the smaller pile runs out. What is left over is all one color, the color of the bigger pile, and it is the sum.
In the figure, -6 + 4 makes four zero pairs, and two shaded counters are left, so -6 + 4 = -2. The number left over is 6 - 4, the bigger pile minus the smaller, and it is negative because the bigger pile was the negative one.
The two pictures say the same thing. On the number line, the steps of the move that bring you back toward zero are the steps that cancel; with counters, they are the zero pairs. In -6 + 4, the move of 4 to the right undoes four of the six steps that -6 is from zero, and four zero pairs cancel four of the six shaded counters.
Part 3: adding without a model
Nobody counts out 38 white counters and 65 shaded ones, but the counters tell you what would happen. Write |a| for the absolute value of a, its distance from zero. That is also the number of counters in the pile for a.
Two integers with the same sign. There are no zero pairs, so the counters simply add up. The size of the sum is |a| + |b|, and the sign is the sign the two numbers share. For example,
Two integers with different signs. The smaller pile is canceled completely, and an equal number from the bigger pile goes with it. What is left is the larger absolute value minus the smaller one, and it has the sign of the number with the larger absolute value, the one farther from zero. For example, in 42 + (-67) the negative number is farther from zero, 67 - 42 = 25, and
Two opposites. If |a| = |b| and the signs differ, every counter is in a zero pair and the sum is 0, which is neither positive nor negative.
| The two numbers | Size of the sum | Sign of the sum |
|---|---|---|
| same sign | \lvert a\rvert + \lvert b\rvert | the sign they share |
| different signs | larger absolute value minus the smaller | the sign of the one farther from zero |
| opposites | 0 | none |
More than two integers. Addition of integers keeps the properties of addition that whole numbers have. The commutative property, a + b = b + a, lets you change the order of the numbers, and the associative property, (a + b) + c = a + (b + c), lets you change which two you add first. So in a long sum you may collect all the positive numbers into one total and all the negative numbers into another, and then combine the two totals. Adding from left to right gives the same answer; collecting first just means only one sum with different signs is left to do.
Brackets and the order of operations work exactly as before: work out what is inside the brackets first, then multiply, then add.
Worked examples
Examples 1 to 3 go with Part 1, the number line. Examples 4 and 5 go with Part 2, the counters. Examples 6 to 10 go with Part 3, adding without a model.
Moves on the number line
Use the number line to find each sum.
(a) -2 + (-5) \qquad (b) -6 + 9
Solution(a) Start at -2. The number -5 is a move of 5 to the left, so count 5 steps left: -3, -4, -5, -6, -7. Both numbers point left, so the sum is farther left than either.
(b) Start at -6. The number 9 is a move of 9 to the right. The first 6 steps bring you to 0, and that leaves 9 - 6 = 3 more steps, which land on 3.
The sum is positive because the move to the right was longer than the distance from -6 back to zero.
A lift between floors
In an office building the street floor is level 0, the floors above it are levels 1, 2, 3 and so on, and the parking floors below it are levels -1, -2, -3 and so on. A lift waits at level -3. It goes up 7 floors, and then down 9 floors. At which level does it stop each time?
SolutionThe lift shaft is a number line standing on end. Going up 7 floors is a move of +7. Start at -3: three floors up reach 0, the street, and the other 4 reach level 4.
Going down 9 floors is a move of -9, so it is added as a negative number. Start at 4: four floors down reach 0, and the other 5 reach level -5.
The lift stops first at level 4, then at level -5, five floors below the street. Writing a trip down as adding a negative number means every trip, up or down, is handled by the same operation.
Finding the missing move
(a) What number must be added to -5 to give 2?
(b) What number must be added to -5 to give -9?
SolutionThe missing number is a move: how far, and which way, takes you from -5 to the target.
(a) From -5 to 0 is 5 steps to the right, and from 0 to 2 is 2 more. That is 7 steps to the right, the move 7. Check: -5 + 7 = 2.
(b) From -5 to -9 is 4 steps to the left, the move -4. Check: -5 + (-4) = -9.
A target to the right of the start needs a positive number, and a target to the left needs a negative one. Asking “what moves me from here to there” is the question that subtraction answers, which is where the next lesson begins.
Four sums with counters
Use counters to find each sum.
(a) -3 + (-5) \qquad (b) 7 + (-4) \qquad (c) -2 + 6 \qquad (d) 5 + (-5)
Solution(a) Three shaded counters and five more shaded counters: eight shaded counters and no zero pairs. The sum is -3 + (-5) = -8.
(b) Seven white counters and four shaded ones. The four shaded counters each pair with a white counter, making four zero pairs, and 7 - 4 = 3 white counters are left. The sum is 7 + (-4) = 3.
(c) Two shaded counters and six white ones. Two zero pairs use up the shaded counters, and 6 - 2 = 4 white counters are left. The sum is -2 + 6 = 4.
(d) Five white counters and five shaded ones make five zero pairs and leave nothing. The sum is 5 + (-5) = 0: the two numbers are opposites.
In (b) and (c) the answer was positive, because there were more white counters than shaded ones. The number of counters left over was the bigger pile minus the smaller each time.
Many piles, one value
Show that each set of counters in the figure is worth -2, and explain why the value does not change when a zero pair is added. Then find how many shaded counters a set must have if it is worth -2 and has 10 white counters.
Set A is two shaded counters, worth -2. Set B is three shaded counters and one white one, -3 + 1: one zero pair, and two shaded counters left, so -3 + 1 = -2. Set C is five shaded and three white counters, -5 + 3: three zero pairs, two shaded left, so -5 + 3 = -2.
Each set is the one before with zero pairs put in. Set B is set A with one zero pair added, and a zero pair is worth 1 + (-1) = 0; adding 0 to a number does not change it. Adding any number of zero pairs therefore leaves the value at -2.
A set worth -2 with 10 white counters needs every white counter to be in a zero pair, which uses 10 shaded counters, and then 2 shaded counters left over. That is 12 shaded counters, and indeed -12 + 10 = -2.
The same number can be shown by many different piles. That freedom is what makes counters useful for subtraction, where you sometimes need counters of a color the pile does not have.
Larger numbers
Find each sum without a model.
(a) 38 + (-65) \qquad (b) -120 + 47 \qquad (c) -46 + (-29) \qquad (d) 91 + (-58)
Solution(a) The signs are different, so the absolute values are subtracted: 65 - 38 = 27. The number farther from zero is -65, so the sum is negative.
(b) Different signs again: 120 - 47 = 73, and -120 is farther from zero.
(c) Both numbers are negative, so their absolute values add, 46 + 29 = 75, and the sum keeps the negative sign.
(d) Different signs: 91 - 58 = 33, and this time the positive number is farther from zero.
Before working out the size, it helps to settle the sign: in (a) a glance at 38 and 65 already says the answer is negative.
Several integers at once
Find -14 + 9 + (-6) + 20 + (-3).
SolutionBy the commutative and associative properties the numbers may be reordered and regrouped, so collect the positive numbers and the negative numbers separately.
Now one sum with different signs is left: 29 - 23 = 6, and 29 is farther from zero.
Check by adding from left to right: -14 + 9 = -5, then -5 + (-6) = -11, then -11 + 20 = 9, then 9 + (-3) = 6. The same answer, but three of those four sums have different signs, where collecting first left only one.
Evaluating expressions
(a) Evaluate x + (-12) when x = -7 and when x = 30.
(b) Evaluate -a + 9 when a = -4.
Solution(a) Replace x by its value, in brackets so the signs stay apart. When x = -7, both numbers are negative, so 7 + 12 = 19 and the sum is negative.
When x = 30, the signs are different: 30 - 12 = 18, and 30 is farther from zero.
(b) The expression -a means the opposite of a. When a = -4, the opposite of -4 is 4, so -a = 4 and
The minus sign in -a does not say that -a is negative; it makes it the opposite of whatever a is.
Brackets first
Simplify each expression.
(a) -9 + 4(-3 + 8) \qquad (b) (-7 + 2) + (12 + (-15))
Solution(a) The order of operations puts the brackets first. Inside them the signs differ: 8 - 3 = 5, and 8 is farther from zero, so -3 + 8 = 5. Then multiply, and add last.
(b) Each bracket is a sum with different signs: -7 + 2 = -5 and 12 + (-15) = -3. Then the two results have the same sign, so their absolute values add.
A score over one evening
In a card game, points won count as positive and points lost as negative. Ines starts the evening on -27 points, carried over from last week. In the next four hands she wins 50 points, loses 22, wins 10 and loses 41. What is her score at the end, and how many points must she win in one more hand to get back to exactly 0?
SolutionEach hand changes the score, a win by a positive number and a loss by a negative one, so her score at the end is
Collect the positive and the negative numbers, as the properties of addition allow.
Then 90 - 60 = 30, and -90 is farther from zero, so her score is -30 points: she is 30 points behind zero. A running total gives the same: -27 + 50 = 23, then 23 + (-22) = 1, then 1 + 10 = 11, then 11 + (-41) = -30.
To bring a score of -30 to 0, add its opposite: -30 + 30 = 0. She must win 30 points.
Boundaries
Counters show integers only. A counter is worth 1 or -1, so no pile of counters is worth -2.5. The number line has no such limit, and the rules of Part 3 hold for every signed number, fractions and decimals included: -2.5 + 4 = 1.5 by the same “subtract the absolute values, take the sign of the one farther from zero”. That extension is adding rational numbers.
The sign rule for different signs needs one number to be farther from zero. When the two numbers are equally far from zero they are opposites, and the sum is 0, which has no sign at all. Only then is “the sign of the larger” without meaning.
Adding no longer always makes a number bigger. With whole numbers, a sum is never less than either of the numbers added. With integers, a + b is greater than a exactly when b is positive, equal to a when b = 0, and less than a when b is negative: 5 + (-2) = 3, which is less than 5.
The reordering and regrouping belong to addition. The commutative and associative properties used in Part 3 are properties of addition, and they fail for subtraction: 5 - 3 = 2 but 3 - 5 = -2. A long sum may be rearranged freely only once every subtraction in it has been written as adding a negative number, which is the step the next lesson takes.
Where this goes next
The question in Example 3, which move takes you from one integer to another, is subtraction. Subtracting integers turns every subtraction into an addition of the opposite number, so that the rules of this lesson do all the work, and the reordering and regrouping of Part 3 become available for any mix of plus and minus signs.
The same rules then carry into signed fractions and decimals, into longer expressions with negative numbers, and into algebra. Collecting like terms such as 7x + (-10x) = -3x is adding integers with a variable attached, which is combining like terms. Solving x + 9 = -4 means finding the missing move from 9 to -4, exactly as in Example 3, and that is the start of solving one-step equations.
Exercises
Part 1: moves on the number line
Use a number line to find each sum.
- -4 + 6
- 5 + (-8)
- -3 + (-6)
- -7 + 7
- On a straight road running east and west, positions east of the town hall are positive and positions west of it are negative, measured in kilometers. A bus is at -2. It drives 9 kilometers east. Where is it now?
- What number must be added to 4 to give -3?
Part 2: counters and zero pairs
Use counters to find each sum, and say how many zero pairs you made.
- -5 + 2
- 6 + (-1)
- -4 + (-4)
- A pile has 7 shaded counters and 3 white counters. Write the addition it shows, and find what it is worth.
- Describe two different piles of counters that are each worth 3, and show that each is worth 3.
Part 3: two integers without a model
- 27 + (-41)
- -63 + 18
- -35 + (-48)
- 150 + (-95)
- -212 + 212
Part 3: several integers and expressions
- 8 + (-15) + 11 + (-6)
- -25 + (-12) + 40 + (-9)
- -6 + 3(-2 + 5)
- Evaluate y + (-17) when (a) y = -8 and (b) y = 22.
- Evaluate -m + 6 when (a) m = 10 and (b) m = -10.
- Find the integer n for which n + (-15) = -6.
Part 3: problems
- A cave explorer is at -90 meters, that is, 90 meters below the cave entrance. She climbs 35 meters and then goes down a shaft of 25 meters. At what height is she now?
- A market stall records its profit each day, a loss counting as a negative profit. Over four days it records a loss of 40 dollars, a profit of 65 dollars, a loss of 15 dollars and a profit of 30 dollars. What is its total profit over the four days?
Reasoning
- Explain, using the number line or counters, why the sum of two negative integers is always negative.
- Without working out the sum, decide whether -347 + 289 is positive or negative, and explain how you know. Then find it.
- The sum of two integers is 0. What must be true about the two integers? Explain with the number line.
- Someone says that adding a number to a always gives an answer bigger than a. For which numbers is that true? Give an example where it fails.
- Use moves on the number line to explain why -9 + 4 and 4 + (-9) land on the same point.
Answers
- 2. Start at -4; four steps right reach 0 and two more reach 2.
- -3. Start at 5; five steps left reach 0 and three more reach -3.
- -9. Start at -3 and move 6 more to the left.
- 0. A move of 7 to the right from -7 lands exactly on 0; the numbers are opposites.
- At 7, that is, 7 kilometers east of the town hall. Driving east is a positive move: -2 + 9 = 7. Two kilometers reach the town hall, at 0, and seven more reach 7.
- -7. From 4 to -3 is 7 steps to the left. Check: 4 + (-7) = -3.
- -3, with 2 zero pairs. Two white counters pair with two of the five shaded ones, leaving three shaded: -5 + 2 = -3.
- 5, with 1 zero pair. The one shaded counter cancels one white counter: 6 + (-1) = 5.
- -8, with no zero pairs. All eight counters are shaded: -4 + (-4) = -8.
- -7 + 3 = -4. Three zero pairs, and four shaded counters are left.
- For example, 3 white counters, worth 3; and 5 white counters with 2 shaded ones, worth 5 + (-2) = 3, since two zero pairs leave three white counters. Any pile with three more white counters than shaded ones works.
- -14. Different signs: 41 - 27 = 14, and -41 is farther from zero.
- -45. Different signs: 63 - 18 = 45, and -63 is farther from zero.
- -83. Same sign: 35 + 48 = 83, kept negative.
- 55. Different signs: 150 - 95 = 55, and 150 is farther from zero.
- 0. The two numbers are opposites, so every counter would be in a zero pair.
- -2. Positives: 8 + 11 = 19. Negatives: -15 + (-6) = -21. Then 19 + (-21) = -2.
- -6. Negatives: -25 + (-12) + (-9) = -46. Then 40 + (-46) = -6.
- 3. Brackets first: -2 + 5 = 3. Then 3(3) = 9, and -6 + 9 = 3.
- (a) -25: -8 + (-17) = -25, same sign. (b) 5: 22 + (-17) = 5, since 22 - 17 = 5 and 22 is farther from zero.
- (a) -4: -m = -10, and -10 + 6 = -4. (b) 16: -m is the opposite of -10, which is 10, and 10 + 6 = 16.
- n = 9. The move -15 goes 15 to the left and lands on -6, so n is 15 to the right of -6. Check: 9 + (-15) = -6.
- -80 meters, that is, 80 meters below the entrance. -90 + 35 + (-25): the negatives give -115, and -115 + 35 = -80.
- A profit of 40 dollars. -40 + 65 + (-15) + 30: positives 95, negatives -55, and 95 + (-55) = 40.
- Starting at a negative number puts you left of zero, and adding a negative number is a further move to the left, so you end farther left of zero than you started, never back at it or past it. With counters: both piles are shaded, so there are no zero pairs and every counter left is worth -1.
- Negative, because -347 is farther from zero than 289: the shaded pile is bigger, so shaded counters are left over. The sum is -58, since 347 - 289 = 58.
- They must be opposites: the same distance from zero on opposite sides, or both 0. The sum starts at the first number and must land on 0, so the move has to cover exactly the distance back to zero, in the direction of zero.
- It is true exactly when the number added is positive. Adding 0 leaves a unchanged, and adding a negative number moves left, to something smaller: 5 + (-2) = 3, which is less than 5.
- -9 + 4 starts at -9 and moves 4 right, landing on -5. 4 + (-9) starts at 4 and moves 9 left: four steps to 0, five more to -5. Starting from 0, each sum is the same two moves, 9 to the left and 4 to the right, made in a different order. Together they go 9 steps left and 4 steps back, whatever the order, so both end 5 to the left of 0.