Ratio tables
One mix is known. How do you lay out many more amounts of the same mix, and tell at a glance whether a list of amounts really keeps it?
Where you are 5 in Equivalent ratios and ratio tables
When you reach for it
Beatrix is hanging wallpaper. The packet says to mix 3 scoops of paste powder with 8 liters of water. One wall needs a small batch and the whole room a large one, and every batch must be the same mix. Rather than work each batch out on its own, she lists them:
| Scoops of powder | Liters of water |
|---|---|
| 3 | 8 |
| 6 | 16 |
| 9 | 24 |
| 12 | 32 |
| 15 | 40 |
Every row equals 3 : 8. A table like this is a ratio table: one column for each quantity, and every row the same ratio scaled by some number. Reach for one when a comparison stays fixed and you want many amounts at once, when an amount is awkward to reach in one step, or to test whether a list of pairs keeps one ratio.
Why scaling both parts keeps a ratio the same is scaling a ratio up or down; one missing number in a pair of equal ratios is finding a missing value. A ratio table lines many such pairs up, so the rows can help each other. Part 1 (day one) builds tables and reads their patterns; Part 2 (day two) fills gaps and tests tables.
The procedure
Part 1: building rows by scaling
Every row of a ratio table is the first row multiplied by one number, the same number in both columns. For 9 scoops, from 3 to 9 is \times 3, so the water is 8 \times 3 = 24 liters. The number may be less than 1: half a batch is \displaystyle \times \frac{1}{2}, which gives 1.5 scoops and 4 liters.
A new row may come from any row already in the table, not only the first, because every row is a scaled copy of every other. From the 12 row, a row for 36 scoops is \times 3, so the water is 32 \times 3 = 96 liters.
The headers give each column’s quantity and unit, in the order of the ratio (ratio language): scoops to liters. The rows may come in any order.
Part 1: adding two rows
Two batches poured into one bucket make a bigger batch of the same mix. So adding two rows, column by column, gives another row of the table. The 6 row and the 9 row give
This is allowed because the 6 row is 3 : 8 times 2 and the 9 row is 3 : 8 times 3. By the distributive property,
so the new row is 3 : 8 times 2 + 3 = 5, a row of the same table. Taking a smaller row away from a larger one works the same way: 15 : 40 take away 6 : 16 leaves 9 : 24.
Adding rows is often the quickest road to an awkward amount: 21 = 9 + 12, so 21 scoops take 24 + 32 = 56 liters. It also explains why, in Beatrix’s table, the scoops go up by 3 and the water by 8 each time: each row is the one above it with the first row added on.
Part 1: the patterns down and across
Down. Moving from one row to another multiplies both columns by the same number. From the 3 row to the 12 row the scoops go \times 4, and so does the water: 8 \times 4 = 32. This scaling number changes from one pair of rows to another, but for any two rows it is the same in both columns.
Across. In every row, the water is the same multiple of the powder. In the first row it is \displaystyle 8 \div 3 = \frac{8}{3} = 2\frac{2}{3}. Scaling a row cannot change that multiple: since \displaystyle 3 \times \frac{8}{3} = 8, multiplying 3 and 8 by the same number keeps the second \displaystyle \frac{8}{3} times the first. So \displaystyle 6 \times \frac{8}{3} = 16, \displaystyle 15 \times \frac{8}{3} = 40, and so on down the table (Figure 1).
The across number turns any amount in the first column into its partner in one step. When tables like this are studied as rules, it is called the constant of proportionality.
Part 2: going through a row of one
Lior hires an electric scooter at 13 dollars for every 4 hours. What do 3 hours cost? From 4 to 3 is not a whole scaling number, so first divide both columns by 4 to reach the row with 1 in it, then multiply by 3:
| Hours | Cost (dollars) |
|---|---|
| 4 | 13 |
| 1 | 3.25 |
| 3 | 9.75 |
One hour costs 13 \div 4 = 3.25 dollars, and 3 hours cost 3 \times 3.25 = 9.75 dollars. From the row of 1, every row is one multiplication away. Its partner, 3.25, is the across number: every cost is 3.25 times its hours. A cost for one hour is a unit rate, which has a lesson of its own.
The 1 can sit in either column. One dollar buys \displaystyle 4 \div 13 = \frac{4}{13} of an hour, the row \displaystyle \frac{4}{13} : 1.
Part 2: filling a gap
A gap sits in a row whose other number is known. Matching that number with the same column of a full row gives the scaling number, and the scaling number gives the gap. When it is awkward, add or take away rows, go through the row of 1, or use the across number. Every road builds a row of the same table, so all land on the same value; take the friendliest.
Part 2: is it a ratio table at all?
A table of pairs is a ratio table only when every row is the same ratio. The quickest test is the across number in every row. If it is the same in all of them, the table is a ratio table; if one row differs, that row is not a scaled copy of the others.
Part 2: the rows as points on a grid
Kwame plants a hedge at 5 saplings for every 2 meters. Four rows of his ratio table are 5 : 2, 10 : 4, 15 : 6 and 20 : 8. Plot each row as a point on a coordinate grid, the first column across and the second up (Figure 2).
The points lie on one straight line that runs back to the corner (0, 0), itself a row: the first row times 0. Every ratio table with numbers above zero plots this way; Example 6 has a table whose points miss the corner.
Worked examples
Building a hedge table
Kwame plants a hedge with 5 saplings for every 2 meters. Make a ratio table of saplings to meters with rows for 4, 10 and 30 meters of hedge.
SolutionThe columns are saplings then meters, and the first row is 5 : 2. In each new row the meters are known, so compare them with the 2 in the first row.
For 4 meters, 4 \div 2 = 2, so 5 \times 2 = 10 saplings. For 10 meters, 10 \div 2 = 5, so 5 \times 5 = 25 saplings. For 30 meters the 10 row is nearer: 30 = 10 \times 3, so 25 \times 3 = 75 saplings.
| Saplings | Meters |
|---|---|
| 5 | 2 |
| 10 | 4 |
| 25 | 10 |
| 75 | 30 |
Check the last row against the first: 30 \div 2 = 15, and 5 \times 15 = 75.
Adding rows of paste
Beatrix’s table has the rows 3 : 8 and 12 : 32, scoops to liters. Using only these rows, (a) how much water goes with 27 scoops? (b) How many scoops go with 88 liters?
Solution(a) Break the scoops into amounts the table has: 27 = 12 + 12 + 3. Adding the matching rows, the water is 32 + 32 + 8 = 72 liters. Check with the across number: \displaystyle 27 \times \frac{8}{3} = 72.
(b) Now the water is known, so break the water up instead: 88 = 32 + 32 + 8 + 8 + 8. The matching scoops are 12 + 12 + 3 + 3 + 3 = 33. Check: \displaystyle 33 \times \frac{8}{3} = 88.
Reading the patterns in a table
Emeka plans a longer hedge with the same spacing. His table of saplings to meters has the rows 5 : 2, 15 : 6, 35 : 14 and 50 : 20. (a) What scaling number takes the 15 row to the 35 row? Show that it is the same in both columns. (b) Find the across number, meters divided by saplings, in every row. (c) How many meters do 45 saplings fill?
Solution(a) In the saplings column, \displaystyle 35 \div 15 = \frac{7}{3} = 2\frac{1}{3}. In the meters column, \displaystyle 14 \div 6 = \frac{7}{3} as well. Check: \displaystyle 6 \times \frac{7}{3} = 14. The scaling number need not be whole; it only has to be the same in both columns.
(b) 2 \div 5 = 0.4, 6 \div 15 = 0.4, 14 \div 35 = 0.4 and 20 \div 50 = 0.4. The same in every row, as it must be: each sapling fills 0.4 meters.
(c) Using the across number, 45 \times 0.4 = 18 meters. Check: 45 = 15 \times 3 and 6 \times 3 = 18.
A row of one for scooter hire
Lior’s scooter costs 13 dollars for every 4 hours. (a) What does a 7 hour hire cost? (b) Rosa pays 35.75 dollars at the same rate. How many hours did she hire for?
Solution(a) From 4 to 7 is not a friendly scaling number, so go through the row of 1: divide both columns by 4, and 1 hour costs 3.25 dollars. Then multiply by 7: 7 \times 3.25 = 22.75. A 7 hour hire costs 22.75 dollars.
(b) Now the cost is known. The row of 1 has cost 3.25, and the scaling number from 3.25 to 35.75 is 35.75 \div 3.25 = 11, so the hours are 1 \times 11 = 11. Rosa hired for 11 hours. Check by adding rows: 11 = 4 + 4 + 3, and 13 + 13 + 9.75 = 35.75.
Filling the gaps
Signe’s table of scoops to liters for Beatrix’s paste has gaps. Fill them.
| Scoops of powder | Liters of water |
|---|---|
| 3 | 8 |
| 9 | ? |
| ? | 40 |
| 4.5 | ? |
| ? | 100 |
In the second row, 9 = 3 \times 3, so the water is 8 \times 3 = 24. In the third, 40 = 8 \times 5, so the scoops are 3 \times 5 = 15. In the fourth, 4.5 is half of 9, and the 9 row is now known, so the water is half of 24, which is 12.
In the last row, 100 \div 8 = 12.5, so the scoops are 3 \times 12.5 = 37.5. Check with the across number: \displaystyle 37.5 \times \frac{8}{3} = 100. The gaps are 24, 15, 12 and 37.5.
Which hire tables are ratio tables?
Three shops list scooter hire as hours to cost in dollars. Rosa’s shop: 2 : 5, 4 : 10, 6 : 15. Emeka’s shop: 1 : 4, 2 : 6, 3 : 8. Signe’s shop: 3 : 7.5, 5 : 12.5, 8 : 20. Which are ratio tables, and do any two of them charge the same rate?
SolutionWork out the across number, cost divided by hours, in every row.
Rosa’s shop: 5 \div 2 = 2.5, 10 \div 4 = 2.5, 15 \div 6 = 2.5. The same each time, so it is a ratio table.
Emeka’s shop: 4 \div 1 = 4, 6 \div 2 = 3, \displaystyle 8 \div 3 = 2\frac{2}{3}. These differ, so it is not a ratio table: doubling 1 hour to 2 takes the cost from 4 to 6 dollars, not 8. The prices fit a fixed charge of 2 dollars plus 2 dollars an hour, and plotted, the points lie on a straight line that meets the upright axis at 2, not at 0.
Signe’s shop: 7.5 \div 3 = 2.5, 12.5 \div 5 = 2.5, 20 \div 8 = 2.5. A ratio table, though its rows do not go up in even steps. Its across number is Rosa’s, so the two shops charge the same rate.
Comparing two pastes with a shared row
Beatrix mixes 3 scoops of powder to 8 liters of water. Kwame mixes 5 scoops to 13 liters. Whose paste is thicker, with more powder in the same water?
SolutionBuild each table until the two share a number in one column. Beatrix’s scoops go 3, 6, 9, 12, 15 and Kwame’s 5, 10, 15. At 15 scoops, Beatrix’s row is 15 : 40 (times 5) and Kwame’s is 15 : 39 (times 3).
The same powder goes into 39 liters for Kwame and 40 for Beatrix, so Kwame’s paste is thicker. The across numbers agree: \displaystyle \frac{8}{3} = 2\frac{2}{3} liters per scoop for Beatrix is more than \displaystyle \frac{13}{5} = 2\frac{3}{5} for Kwame. More on this is in comparing two ratios.
Boundaries
Every row must be the same ratio. A row is made by multiplying both numbers by one number, or by adding or taking away whole rows. Adding the same amount to both columns does not make a row: from 3 : 8, adding 1 to each part gives 4 : 9, a different mix. Nor does multiplying two rows together.
The columns keep their order and their units. The first number of every row counts the same thing in the same unit; rows may be listed in any order, but columns cannot swap in some rows.
The first row needs numbers above zero. The row 0 : 0 belongs to every ratio table, but no scaling number leads away from it, so it cannot be the row a table is built from.
The setting may not allow every row. The hedge table has the row 2.5 : 1, two and a half saplings for one meter. It is a true row, but nobody plants half a sapling, so it is a rate to work with rather than a planting plan.
Not every rule makes a ratio table. A price with a fixed charge on top, like Emeka’s shop in Example 6, does not.
Where this goes next
The row of 1 starts unit rates, and the across number becomes the constant of proportionality. A double number line shows the same pairs as matching marks on two lines, and a tape diagram handles a ratio when the total is known. Two rows written as one statement are a proportion, and solving a proportion finds a gap when no friendly row is in sight.
Exercises
Part 1: building rows by scaling
- Complete the ratio table of saplings to meters that starts 5 : 2, with the rows 25 : \,?, 55 : \,? and 100 : \,?.
- Complete the ratio table of hours to cost in dollars that starts 4 : 13, with the rows 12 : \,?, 40 : \,? and 2 : \,?.
- Complete the ratio table that starts 7 : 2, with the rows 14 : \,?, ? : 10 and 70 : \,?.
- Complete the ratio table that starts 14 : 35, with the rows 2 : \,?, 6 : \,? and 20 : \,?.
Part 1: adding two rows
- A table of saplings to meters has the rows 5 : 2 and 15 : 6. Using only adding or taking away rows, find the meters for 20, 10 and 40 saplings.
- A table of hours to cost in dollars has the rows 4 : 13 and 6 : 19.5. By adding rows, find the cost of 10 hours and of 16 hours.
- A table of scoops to liters has the rows 3 : 8 and 24 : 64. Using only these rows, find the liters for 39 scoops and for 45 scoops.
Part 1: patterns down and across
- A ratio table has the rows 6 : 21, 10 : 35, 14 : 49 and 22 : 77. (a) Find the across number, second divided by first. (b) Find the scaling number from the 6 row to the 22 row, and show it is the same in both columns.
- In Beatrix’s table of scoops to liters, first row 3 : 8, what is the across number? Use it to find the liters for 18 scoops and for 7.5 scoops.
- In Kwame’s hedge, 5 saplings for every 2 meters, how many meters does one sapling fill? How many meters do 60 saplings fill?
Part 2: through a row of one
- At 13 dollars for every 4 hours, what do 5 hours and 9 hours of scooter hire cost?
- At 5 saplings for every 2 meters, find the saplings for 1 meter, 16 meters and 26 meters.
- A ratio table starts 6 : 10. Find the row with 1 in the first column, then the row 9 : \,?. Then find the row with 1 in the second column.
Part 2: filling gaps
- Fill the gaps in the ratio table 8 : 6, 4 : \,?, ? : 15, 28 : \,?.
- Fill the gaps in the ratio table of scoops to liters 3 : 8, ? : 28, 0.75 : \,?, ? : 60.
- Fill the gaps in the ratio table of hours to cost in dollars 4 : 13, ? : 52, 13 : \,?, ? : 55.25.
Part 2: is it a ratio table?
- Hours to cost in dollars: 2 : 7, 3 : 10, 5 : 16. Is this a ratio table?
- Is 4 : 6, 6 : 9, 10 : 15, 16 : 24 a ratio table? If so, give its across number.
- Saplings to meters: 5 : 2, 10 : 4, 15 : 7. Is this a ratio table? If not, which row breaks it, and what should that row be?
Part 2: in context
- Rosa mixes paste at 4 scoops to 11 liters. Is her paste thicker or thinner than the packet’s 3 scoops to 8 liters?
- One shop hires scooters at 13 dollars for every 4 hours, another at 20 dollars for every 6 hours. Which is cheaper for 12 hours, and by how much?
- The rows 3 : 8 and 6 : 16 are plotted as the points (3, 8) and (6, 16). Does the point (4.5, 12) lie on the same line through (0, 0)? Does (9, 25)?
Reasoning
- Explain why adding two rows of a ratio table always gives another row of the same table. Use the rows 6 : 16 and 9 : 24 of the table that starts 3 : 8.
- From the row 3 : 8 to the row 6 : 16, the scoops go up by 3 and the liters by 8, yet both columns are multiplied by 2. Explain why the scaling number is the same in both columns while the amount added is not.
- Can one ratio table contain both the rows 3 : 8 and 8 : 3? Explain.
Answers
- 10, 22 and 40 meters. The scaling numbers are 5, 11 and 20, and 2 \times 5 = 10, 2 \times 11 = 22, 2 \times 20 = 40.
- 39, 130 and 6.5 dollars. The scaling numbers are 3, 10 and \displaystyle \frac{1}{2}, and 13 \times 3 = 39, 13 \times 10 = 130, 13 \div 2 = 6.5.
- 14 : 4, 35 : 10 and 70 : 20. The scaling numbers are 2, 5 and 10.
- 2 : 5, 6 : 15 and 20 : 50. Dividing by 7 gives 2 : 5, then \times 3 and \times 10.
- 8, 4 and 16 meters. 20 = 15 + 5 gives 6 + 2 = 8; 10 = 15 - 5 gives 6 - 2 = 4; 40 = 15 + 15 + 5 + 5 gives 6 + 6 + 2 + 2 = 16.
- 32.5 dollars and 52 dollars. 10 = 4 + 6 gives 13 + 19.5 = 32.5; 16 = 10 + 6 gives 32.5 + 19.5 = 52.
- 104 liters and 120 liters. 39 = 24 + 3 + 3 + 3 + 3 + 3 gives 64 + 5 \times 8 = 104; 45 = 24 + 24 - 3 gives 64 + 64 - 8 = 120.
- (a) 3.5, since 21 \div 6 = 35 \div 10 = 49 \div 14 = 77 \div 22 = 3.5. (b) \displaystyle 3\frac{2}{3}: \displaystyle 22 \div 6 = \frac{11}{3} and \displaystyle 77 \div 21 = \frac{11}{3}.
- The across number is \displaystyle \frac{8}{3} = 2\frac{2}{3}. Then \displaystyle 18 \times \frac{8}{3} = 48 liters and \displaystyle 7.5 \times \frac{8}{3} = 20 liters.
- 0.4 meters, since 2 \div 5 = 0.4. Then 60 \times 0.4 = 24, so 24 meters.
- 16.25 dollars and 29.25 dollars. The row of 1 is 1 : 3.25, and 5 \times 3.25 = 16.25, 9 \times 3.25 = 29.25.
- 2.5, 40 and 65 saplings. Dividing 5 : 2 by 2 gives 2.5 : 1, and 16 \times 2.5 = 40, 26 \times 2.5 = 65.
- \displaystyle 1 : 1\frac{2}{3}, then 9 : 15, then 0.6 : 1. Divide by 6, then \displaystyle 9 \times \frac{5}{3} = 15; divide 6 : 10 by 10.
- 3, 20 and 21. 4 is half of 8, so half of 6 is 3; 15 \div 6 = 2.5 and 8 \times 2.5 = 20; 28 \div 8 = 3.5 and 6 \times 3.5 = 21.
- 10.5, 2 and 22.5. 28 \div 8 = 3.5 and 3 \times 3.5 = 10.5; \displaystyle 0.75 \times \frac{8}{3} = 2; 60 \div 8 = 7.5 and 3 \times 7.5 = 22.5.
- 16, 42.25 and 17. The row of 1 is 1 : 3.25: 52 \div 3.25 = 16, 13 \times 3.25 = 42.25, 55.25 \div 3.25 = 17.
- No. The across numbers 7 \div 2 = 3.5, \displaystyle 10 \div 3 = 3\frac{1}{3}, 16 \div 5 = 3.2 differ.
- Yes, with across number 1.5: 6 \div 4 = 9 \div 6 = 15 \div 10 = 24 \div 16 = 1.5.
- No. The first two rows have across number 0.4, but 7 \div 15 is not 0.4. The third row should be 15 : 6, since 15 \times 0.4 = 6.
- Thinner. At 12 scoops the packet gives 12 : 32 and Rosa 12 : 33: the same powder in more water.
- The first shop, by 1 dollar. For 12 hours the first charges 13 \times 3 = 39 dollars and the second 20 \times 2 = 40 dollars.
- (4.5, 12) does, because \displaystyle 4.5 \times \frac{8}{3} = 12. (9, 25) does not: the row for 9 is 9 : 24, so (9, 25) sits just above the line.
- The 6 row is 3 : 8 times 2 and the 9 row is 3 : 8 times 3. By the distributive property, 3 \times 2 + 3 \times 3 = 3 \times (2 + 3) and 8 \times 2 + 8 \times 3 = 8 \times (2 + 3), so the sum 15 : 40 is 3 : 8 times 5, a row of the same table. Any two rows work the same way, with their own scaling numbers.
- Scaling multiplies each part by the same number, so the scaling number is shared. The amount added is the starting number times one less than the scaling number, 3 \times 1 = 3 and 8 \times 1 = 8, so it differs whenever the starting numbers differ.
- No. The across number of 3 : 8 is \displaystyle \frac{8}{3} and that of 8 : 3 is \displaystyle \frac{3}{8}, and a ratio table has the same across number in every row.