Grade 2 · 2.NBT.A.3 · 4.NBT.A.2

Expanded form

The counter at the museum door says 438. How much of that number does each digit carry, and can the number be taken apart into those amounts and put back together again?

Where you are 15 in Place value

Why this exists

A museum has a counter at its front door. Every time a visitor walks in, the number on the counter goes up by one. At noon it shows 438. Alemayehu, Oyuun and Kiele are on a class trip, and they want to know what that number is made of.

The The place value chart lesson answered one part of that: each digit is worth an amount that depends on its column. The 4 is worth 400, the 3 is worth 30 and the 8 is worth 8. This lesson puts those amounts back together. The number is the three amounts added up:

438 = 400 + 30 + 8

Writing a number this way is called expanded form. It shows in one line what is hidden in the short way of writing. The short form 438 is quick to write and read. The expanded form 400 + 30 + 8 shows how much each digit carries. Both name the same number.

Going the other way matters just as much. A sum of hundreds, tens and ones can be put back into a single number, even when the parts come in a jumble or a part is too big for one column. That is how blocks, bags and crates get counted, and it is the first step of adding and subtracting three-digit numbers by place value.

The lesson runs over three days.

  • Day 1, from a number to its parts. Writing a three-digit number as hundreds plus tens plus ones, from the digits, from blocks and from words.
  • Day 2, zero digits. A digit 0 is worth nothing, so its part is left out: 706 = 700 + 6.
  • Day 3, from the parts back to the number. Parts given out of order, like 40 + 5 + 600, and parts that are not one per place, like 400 + 17.

Base ten blocks, a sheet of paper for the sums and a set of digit cards are all the lesson needs.

Definition

The expanded form of a number is the number written as a sum of the values of its digits, one part for each digit that is not 0, largest part first.

For a three-digit number the parts are:

  • the hundreds part, the hundreds digit followed by two zeros, such as 400;
  • the tens part, the tens digit followed by one zero, such as 30;
  • the ones part, the ones digit itself, such as 8.

So 438 = 400 + 30 + 8. A digit 0 has the value 0, and adding 0 changes nothing, so its part is left out: 706 = 700 + 6, and 900 is its own expanded form.

The same number can also be written in unit form, with the place names in words: 4 hundreds + 3 tens + 8 ones. Unit form and expanded form say the same thing. Unit form names the block; expanded form says what that many blocks are worth.

Intuition

Day 1: one part for each kind of block

Build 438 with base ten blocks from Base ten blocks and trading ten for one: 4 flats, 3 rods and 8 small squares. Now look at the blocks one kind at a time. The flats are worth 400. The rods are worth 30. The small squares are worth 8. Those three amounts are the three parts of the expanded form, and pushing the three groups together is adding them (Figure 1).

400 + 30 + 8 = 438
Figure 1Each group of blocks is one part. Together the parts make 438 = 400 + 30 + 8.

So a sum in expanded form is a written record of a pile of blocks sorted by kind. The plus signs stand where the gaps between the groups are. Reading the sum aloud gives the number name almost word for word: “four hundred” is 400, “thirty” is 30, “eight” is 8. Number names were the work of Reading and writing numbers to 1,000.

Day 2: no blocks, no part

Some numbers have a kind of block missing. The museum counter shows 706 at closing time. That is 7 flats, no rods and 6 small squares. There is nothing in the tens group to write down, so the expanded form has only two parts (Figure 2).

700 + 6 = 706
Figure 2No rods, so no tens part. The blocks show 706 = 700 + 6.

Writing 700 + 0 + 6 is not wrong: adding zero changes nothing, so it still equals 706. The shorter 700 + 6 is the usual way, the same way nobody lists an empty group of blocks.

Here is something worth stopping on. In the number 706 the 0 must be written, because it holds the tens column open and keeps the 7 in the hundreds column (The place value chart). In the sum 700 + 6 no zero digit is needed in the middle. Each part carries its own zeros at its right end, so 700 already says “hundreds” without any column around it.

Day 3: every part knows its own place

That last point is what makes going backward easy. A part such as 600 is worth 6 hundreds wherever it sits in the sum. So the parts can come in any order. The sum 40 + 5 + 600 still has 6 hundreds, 4 tens and 5 ones, and the number is 645. Changing the order of the parts leaves the sum the same; this is the commutative property of addition.

A part may also be bigger than one digit’s worth. Four crates of 100 ears of corn and 17 loose ears make 400 + 17. The 17 is 1 ten and 7 ones, so the sum is 400 + 10 + 7, which is 417. The trade of ten ones for one ten is the one from Base ten blocks and trading ten for one; here it is done in the numbers instead of with the blocks (Figure 3).

400 + 17 400 + 10 + 7 = 417
Figure 3Ten of the 17 small squares become one rod. The total stays 417.

Results

A three-digit number is the sum of its parts. If a number has hundreds digit a, tens digit b and ones digit c, it is the sum of a hundreds, b tens and c ones. For example, 438 = 400 + 30 + 8.

A zero digit gives no part. Its value is 0, and adding 0 changes nothing: 706 = 700 + 6, 260 = 200 + 60, 400 = 400.

The order of the parts does not matter. By the commutative property of addition, 40 + 5 + 600 = 600 + 40 + 5 = 645.

Parts that are not one per place can be traded into place. Ten ones are one ten and ten tens are one hundred, so a sum like 400 + 17 becomes 400 + 10 + 7 = 417, and 200 + 160 + 3 becomes 300 + 60 + 3 = 363.

Why it is true

Each digit of a number counts one kind of block: the hundreds digit counts flats, the tens digit counts rods, the ones digit counts small squares (The place value chart). The number is how many small squares all the blocks are worth together. Counting the flats’ worth, then the rods’ worth, then the small squares’ worth, and adding, counts every block exactly once. So the number equals the sum of its parts.

A digit 0 counts no blocks of its kind, so its part is 0. Adding 0 leaves a sum the same, which is why that part can be dropped.

Adding the same amounts in a different order gives the same total; this is the commutative property. Grouping them differently, such as adding 200 and 100 first, also gives the same total; this is the associative property. That is why parts may be read in any order and why two parts in the same place may be joined into one.

Worked examples

Examples 1 to 3 go with Day 1, Examples 4 and 5 with Day 2, and Examples 6 and 7 with Day 3.

Example 1

Day 1: The counter at noon

At noon the visitor counter at the museum door shows 438. Alemayehu wants to write the number as the sum of what its digits are worth. What does he write?

Solution

Find each digit’s place by counting from the right end. The 8 is in the ones place, the 3 in the tens place and the 4 in the hundreds place.

The 4 counts hundreds, so it is worth 400. The 3 counts tens, so it is worth 30. The 8 counts ones, so it is worth 8. Add the three parts, largest first:

438 = 400 + 30 + 8

Check by adding back: 400 + 30 = 430, and 430 + 8 = 438. Figure 1 shows the same sum with blocks. In unit form it is 4 hundreds + 3 tens + 8 ones.

Example 2

Day 1: From blocks to the sum

Oyuun builds a number with 2 flats, 5 rods and 8 small squares. Write it in expanded form and as a number.

Solution

Take the blocks one kind at a time. Two flats are 2 hundreds, worth 200. Five rods are 5 tens, worth 50. Eight small squares are worth 8. So the blocks show

200 + 50 + 8 = 258

The number has one digit for each kind of block: 2 for the flats, 5 for the rods and 8 for the small squares, in that order. It reads two hundred fifty-eight, and the words follow the parts: “two hundred” is 200, “fifty” is 50, “eight” is 8.

Example 3

Day 1: From words to the sum

Kiele finds a card on a display case: “9 hundreds, 1 ten, 7 ones”. Write the number in expanded form and as a number. Which part is hidden by the number’s name?

Solution

Nine hundreds are worth 900. One ten is worth 10. Seven ones are worth 7. So

900 + 10 + 7 = 917

The name is nine hundred seventeen. “Seventeen” sounds like one word, but it is 10 + 7: the 1 in the tens place is worth 10, not 1. The expanded form shows the ten that the name hides, as in Teen numbers as ten and some more.

Example 4

Day 2: The counter at closing time

At closing time the visitor counter shows 706. Write it in expanded form.

Solution

The 7 is in the hundreds place, worth 700. The 0 is in the tens place, worth 0 tens, which is 0. The 6 is in the ones place, worth 6.

The full sum is 700 + 0 + 6. Adding 0 changes nothing, so the tens part is left out:

706 = 700 + 6

Figure 2 shows the blocks: 7 flats and 6 small squares, with no rods at all. The number 706 needs its 0 to keep the 7 in the hundreds place. The sum 700 + 6 does not need it, because 700 carries its own two zeros.

Example 5

Day 2: Three rooms, three counters

Each room of the museum has its own counter. Kiele reads 260 in the dinosaur room, 400 in the rock room and 509 in the space room. Write each number in expanded form.

Solution

Take each number place by place, and leave out any part whose digit is 0.

260 has 2 hundreds, 6 tens and 0 ones. The ones part is 0, so it is left out: 260 = 200 + 60.

400 has 4 hundreds, 0 tens and 0 ones. Only the hundreds part is left: 400 = 400. A number with one part is its own expanded form.

509 has 5 hundreds, 0 tens and 9 ones. The tens part is left out: 509 = 500 + 9.

So a three-digit number can have three parts, two parts or one part. It always has a hundreds part, because a three-digit number never starts with 0.

Example 6

Day 3: Parts out of order

Oyuun is on a museum hunt. The clue says: “Find case number 40 + 5 + 600.” Which case should she look for?

Solution

Each part says its own place, wherever it sits in the sum. The 600 is 6 hundreds. The 40 is 4 tens. The 5 is 5 ones.

Put the parts in order, largest first. Changing the order of addends does not change a sum; that is the commutative property:

40 + 5 + 600 = 600 + 40 + 5 = 645

Oyuun looks for case 645. Check by adding in the order given: 40 + 5 = 45, and 45 + 600 = 645. Both ways give the same number.

Example 7

Day 3: Too many in one place

After the museum, the class visits a farm with a corn maze. Kiele helps pack ears of corn. A crate holds 100 ears, a bag holds 10 ears, and some ears are left loose.

(a) On the first table there are 4 crates and 17 loose ears. How many ears is that?

(b) On the second table there are 2 crates, 16 bags and 3 loose ears. How many ears is that?

Solution

(a) The crates hold 400 ears, so the table has 400 + 17 ears. The part 17 is too big for the ones place: it is 1 ten and 7 ones. Ten loose ears fill one bag. So

400 + 17 = 400 + 10 + 7 = 417

There are 417 ears. Figure 3 shows the same trade with blocks: ten of the 17 small squares become one rod.

(b) The crates hold 200 ears and the bags hold 160. So the table has 200 + 160 + 3 ears. The part 160 is 16 tens, too many for the tens place. Ten bags make one crate, so 160 = 100 + 60:

\begin{aligned} 200 + 160 + 3 &= 200 + 100 + 60 + 3 \\ &= 300 + 60 + 3 \\ &= 363 \end{aligned}

Joining 200 and 100 into 300 first is regrouping the sum, the associative property. There are 363 ears. In each part the trade is the one from Base ten blocks and trading ten for one, done with numbers instead of blocks.

Boundaries

  • Expanded form here is for whole numbers up to 999. Bigger numbers get more parts, one for each further place, as in Numbers to one million.
  • The expanded form has exactly one part for each digit that is not 0. A sum such as 400 + 17 or 200 + 160 + 3 is equal to the number, but it is not its expanded form until every part is one digit followed by zeros, with at most one part for each place.
  • A digit 0 gives no part, but the 0 is still needed when the number is written the short way: 706 and 76 are different numbers.
  • The number 0 has no digits other than 0, so it has no parts at all; it is simply written 0.
  • The parts are joined with + only. Every part is a whole number of hundreds, tens or ones.

Where this goes next

Adding two three-digit numbers can start from their expanded forms, hundreds with hundreds, tens with tens and ones with ones; that is The partial sums method. Subtracting works the same way, in Subtracting three-digit numbers by place value, including across zero, and comparing two numbers part by part, largest part first, is Comparing and ordering whole numbers. Later, each part is written as a digit times 100, 10 or 1, which is how Partial products breaks up a multiplication, and the same idea reaches to the right of the decimal point in Thousandths: reading, writing and expanded form.

Exercises

Day 1: from a number to its parts

  1. Write 563 in expanded form.
  2. Write 218 in expanded form.
  3. Write 581 in expanded form.
  4. Alemayehu builds a number with 3 flats, 8 rods and 1 small square. Write it in expanded form and as a number.
  5. Write “6 hundreds, 4 tens, 9 ones” in expanded form and as a number.
  6. A museum counter reads 925. Write it in expanded form. Which part is the biggest, and which digit gives it?
  7. Which number has the expanded form 100 + 80 + 9?

Day 2: zero digits

  1. Write 803 in expanded form.
  2. Write 360 in expanded form.
  3. Write 900 in expanded form.
  4. Write 102 in expanded form.
  5. The museum counter shows 780 in the morning. Later it shows 708. Write both numbers in expanded form.
  6. Is 300 + 0 + 8 equal to 308? What is the expanded form of 308?

Day 3: from the parts back to the number

  1. What number is 50 + 4 + 300?
  2. What number is 6 + 500?
  3. What number is 90 + 700?
  4. What number is 800 + 19?
  5. What number is 200 + 40 + 30 + 5?
  6. What number is 600 + 150 + 3?
  7. Fill in the box: 782 = 700 + \square + 2.
  8. At the corn maze farm, Kiele counts 5 crates of 100 ears, 13 bags of 10 ears and 4 loose ears. Write the total as a sum of three parts, then as a number.

Explain

  1. Explain why a digit 0 gives no part in expanded form.
  2. Are 300 + 40 + 2 and 2 + 40 + 300 the same number? Explain, and name the property.
  3. A three-digit number has no digit 0. How many parts does its expanded form have? Explain.
  4. Write 540 and 504 in expanded form. Use the parts to explain which number is bigger.
Answers
  1. 563 = 500 + 60 + 3. The 5 is worth 5 hundreds, the 6 is worth 6 tens, and the 3 is worth 3 ones.
  2. 218 = 200 + 10 + 8. The 1 is in the tens place, so its part is 10.
  3. 581 = 500 + 80 + 1.
  4. 300 + 80 + 1 = 381. Three flats are worth 300, eight rods 80, one small square 1.
  5. 600 + 40 + 9 = 649. Six hundreds are 600, four tens are 40, nine ones are 9.
  6. 925 = 900 + 20 + 5. The biggest part is 900, given by the 9 in the hundreds place.
  7. 189. One hundred, 8 tens and 9 ones: 100 + 80 + 9 = 189.
  8. 803 = 800 + 3. The tens digit is 0, so there is no tens part.
  9. 360 = 300 + 60. The ones digit is 0, so there is no ones part.
  10. 900 = 900. Both the tens and ones digits are 0, so the hundreds part is the only one.
  11. 102 = 100 + 2. The tens digit is 0.
  12. 780 = 700 + 80 and 708 = 700 + 8. In 780 the 8 is in the tens place and the ones part is missing; in 708 the 8 is in the ones place and the tens part is missing.
  13. Yes, 300 + 0 + 8 = 308, since adding 0 changes nothing. The expanded form leaves the zero part out: 308 = 300 + 8.
  14. 354. Largest part first: 300 + 50 + 4 = 354. Changing the order does not change the sum.
  15. 506. The parts are 5 hundreds and 6 ones, with no tens: 500 + 6 = 506.
  16. 790. The parts are 7 hundreds and 9 tens, with no ones: 700 + 90 = 790.
  17. 819. The 19 is 1 ten and 9 ones: 800 + 10 + 9 = 819.
  18. 275. Two tens parts can be joined: 40 + 30 = 70, so 200 + 70 + 5 = 275.
  19. 753. The 150 is 1 hundred and 5 tens: 600 + 100 + 50 + 3 = 700 + 50 + 3 = 753.
  20. \square = 80. The 8 in 782 is in the tens place, so the missing part is 80: 700 + 80 + 2 = 782.
  21. 500 + 130 + 4 = 634. The 13 bags are 130 ears, which is 1 hundred and 3 tens, so 500 + 100 + 30 + 4 = 600 + 30 + 4 = 634.
  22. A digit 0 counts no blocks of its kind, so its part is worth 0. Adding 0 to a sum leaves it the same, so writing the part or leaving it out gives the same number. The expanded form leaves it out.
  23. Yes, both are 342. The same three parts are added in a different order, and the commutative property of addition says the order of the addends does not change the sum.
  24. Three. Each digit that is not 0 gives one part, and a three-digit number has three digits. If none of them is 0, each gives a part: a hundreds part, a tens part and a ones part.
  25. 540 = 500 + 40 and 504 = 500 + 4. Both have the hundreds part 500. The rest is 40 in one and 4 in the other, and 40 is more than 4. So 540 is bigger.
kg1128 · updated 2026-10-21 · CC-BY-SA-4.0