Grade 3 · 3.OA.C.7

Facts for seven, eight and nine

After the zeros, ones, twos, threes, fours, fives, sixes and tens, only six facts are left. How can 9 \times 7, 8 \times 9 and 7 \times 7 be built from facts you already know?

Where you are 4 in Multiplication facts

When you reach for it

By now a child knows the twos, fives and tens from Facts for two, five and ten, and the threes, fours and sixes from Facts for three, four and six. Zero groups give 0 and one group gives the other factor, so the zeros and ones are known too. The commutative property lets each fact count for both orders, so 7 \times 4 is already known as 4 \times 7. Once all of that is in place, only six facts of the table are still new:

7 \times 7, \quad 7 \times 8, \quad 7 \times 9, \quad 8 \times 8, \quad 8 \times 9, \quad 9 \times 9

These are the largest products in the table and the ones that take longest to settle. This lesson builds each of them from a fact that is already known, with a move that fits the factor:

  • 9 is one less than 10, so a nine fact is a ten fact take away one group;
  • 8 is 2 \times 2 \times 2, so an eight fact is the other factor doubled three times;
  • 7 is 5 + 2, so a seven fact is a five fact and a two fact added.

Each move rests on a property. The first and third are the The distributive property, which lets a factor be split into parts. The second is the associative property: in a product of three or more numbers, which pair is multiplied first does not change the answer.

Reach for these moves whenever one of the six facts is half remembered. The setting is a scout troop and the relay race it runs at its summer field day.

The lesson takes four days, one part each. The aim of the fourth day is the whole table: every product from 1 \times 1 to 10 \times 10 comes without rebuilding it, with the moves kept as the way to check.

The procedure

Each part gives one family, says which property makes the move correct, and shows it as an array: rows of equal groups, as in Arrays.

Part 1: nines are tens take away one group

At the relay race, Isaure’s troop fields 9 teams with 7 runners on each team. The number of runners is 9 \times 7. The tens are easy: 10 teams of 7 would be 10 \times 7 = 70. Nine teams is one team fewer, so take one group of 7 away.

Draw it as an array of ten rows of 7 and strike out the last row.

7 9 1 9 × 7 = 63 take away 1 × 7 = 7 10 × 7 = 70 in all
Figure 1Ten rows of 7 with one row taken away leave nine rows of 7, 70 - 7 = 63.
\begin{aligned} 9 \times 7 &= (10 - 1) \times 7 \\ &= (10 \times 7) - (1 \times 7) \\ &= 70 - 7 \\ &= 63 \end{aligned}

The distributive property works with take-away as well as with adding: the 9 was written as 10 - 1, the 7 multiplied each part, and the second product was taken from the first. In plain words, a nine fact is a ten fact take away one group. The group taken away is a whole group of the other factor, here a whole row of 7.

The subtraction is always a ten fact minus a one-digit number, which can be done by counting back or by going down to the ten below. For 90 - 9: take away 10 to reach 80, then give back the 1 that was taken too many, 81.

FactTen factTake away one groupProduct
9 \times 330327
9 \times 440436
9 \times 660654
9 \times 770763
9 \times 880872
9 \times 990981

By the commutative property each row is also a column: 7 \times 9 = 9 \times 7 = 63. The nines products also have a digit pattern of their own, which Patterns in the multiplication table takes up.

Part 2: eights are doubles, three times over

Malin packs tent bags for the troop, 8 bags with 9 tent stakes in each. The count is 8 \times 9. Eight is 2 \times 2 \times 2, so the count can be reached by doubling.

  • Two bags hold 2 \times 9 = 18.
  • Four bags are two sets of two bags: 18 + 18 = 36.
  • Eight bags are two sets of four bags: 36 + 36 = 72.
9 1 1 × 9 = 9 1 1 × 9 = 9 2 × 9 = 18 2 2 × 9 = 18 2 2 × 9 = 18 4 × 9 = 36 4 4 × 9 = 36 4 4 × 9 = 36 8 × 9 = 72
Figure 2Each array is two copies of the one above it, so 8 \times 9 is 9 doubled three times, 18, 36, 72.
9 \;\to\; 18 \;\to\; 36 \;\to\; 72

Why doubling three times gives eight groups: the associative property lets the factors be grouped in any way, so

\begin{aligned} 8 \times 9 &= (2 \times 2 \times 2) \times 9 \\ &= 2 \times \bigl(2 \times (2 \times 9)\bigr) \\ &= 2 \times (2 \times 18) \\ &= 2 \times 36 = 72 \end{aligned}

Each “2 \times” is one doubling. An eight fact is the other factor doubled three times. The second doubling gives the four fact, so an eight fact is also a four fact doubled: 8 \times 9 is double 4 \times 9.

FactDouble onceDouble twiceDouble three times
8 \times 361224
8 \times 481632
8 \times 6122448
8 \times 7142856
8 \times 8163264
8 \times 9183672

The last doubling is the one that needs care, because it adds two numbers in the twenties or thirties. Add the tens and the ones apart: 36 + 36 is 60 and 12, which is 72.

Every eight fact ends in a doubling, so every product of 8 is even. Part 1 gives a second route to the same products: 9 \times 8 is 80 - 8 = 72, the same as 8 \times 9.

Part 3: sevens are fives and twos

Lennart sets out cones for relay practice in 7 rows of 7. The count is 7 \times 7. Seven does not split into equal parts, but it does split as 5 + 2, and both of those are known. Cut the array after the fifth column.

7 5 2 7 × 5 = 35 7 × 2 = 14
Figure 3Seven rows of 7 cut after the fifth column are 7 \times 5 and 7 \times 2, 35 + 14 = 49.
\begin{aligned} 7 \times 7 &= 7 \times (5 + 2) \\ &= (7 \times 5) + (7 \times 2) \\ &= 35 + 14 \\ &= 49 \end{aligned}

This is the distributive property again, with the second factor split this time. A seven fact is a five fact and a two fact added. The cut can run either way: cutting after the fifth row instead splits the first 7, and gives the same 35 + 14.

Of the six facts, 7 \times 7 is the only one with no eight or nine in it, so it is the only one that has to come from the sevens. The other two seven facts are already reached from Parts 1 and 2 by the commutative property: 7 \times 8 = 8 \times 7 = 56 and 7 \times 9 = 9 \times 7 = 63. The sevens move then gives each of them a second route, and a second route is a check:

FactFive fact and two factOther routeProduct
7 \times 735 + 14(6 \times 7) + 7 = 42 + 749
7 \times 840 + 16(6 \times 8) + 8 = 48 + 856
7 \times 945 + 1870 - 763

Part 4: the whole table

Here are the seven, eight and nine rows in full, from 1 to 10:

\times 1\times 2\times 3\times 4\times 5
7714212835
8816243240
9918273645
\times 6\times 7\times 8\times 9\times 10
74249566370
84856647280
95463728190

Most of these cells were known before this lesson: the columns for 1, 2, 5 and 10 from the easy facts, and the columns for 3, 4 and 6 from the middle block. Only the cells under \times 7, \times 8 and \times 9 are new. Those nine cells hold the six new facts: 7 \times 8, 7 \times 9 and 8 \times 9 appear twice, once in each order, and 7 \times 7, 8 \times 8 and 9 \times 9 once each. With them, every fact from 1 \times 1 to 10 \times 10 is known.

Fluency means the product comes to mind without rebuilding it. It grows from using the facts. The moves are what make that safe: a fact half remembered can always be rebuilt and checked by a second route. Three habits help on this last day.

Choose the move that fits. A nine is closest to a ten, an eight is a chain of doubles, a seven splits as 5 + 2. When both factors are big, either one can lead. For 8 \times 9, doubling 9 three times and taking 8 from 80 both work, and the two together are a check.

One group more or less. Neighbors in a row differ by one group. If 8 \times 8 = 64 is known, then 8 \times 9 is one more eight, 64 + 8 = 72, and 8 \times 7 is one less, 64 - 8 = 56. This is the distributive property with the factor split as 8 + 1 or written as 8 - 1.

Run it backward. Every fact answers a missing-factor question. If 72 granola bars are shared by 8 patrols, each patrol’s share is the number in 8 \times \square = 72. Searching the eights for 72 finds 8 \times 9. This is division, and Division facts takes it up for the whole table.

Worked examples

Examples 1 and 2 go with Part 1, Examples 3 and 4 with Part 2, Examples 5 and 6 with Part 3, and Examples 7 and 8 with Part 4.

Example 1

Nine teams of seven

At the relay race, Isaure’s troop fields 9 teams with 7 runners on each team. How many runners does the troop field?

Solution

Nine teams of 7 is 9 \times 7. Ten teams would be the ten fact 10 \times 7 = 70. Nine teams is one team fewer, so one group of 7 comes off. The distributive property, with 9 written as 10 - 1, says

9 \times 7 = (10 \times 7) - (1 \times 7) = 70 - 7 = 63

This is the array in Part 1. The troop fields 63 runners.

Check with a different split. Nine teams are 5 teams and 4 teams, so (5 \times 7) + (4 \times 7) = 35 + 28 = 63.

Example 2

Rows of chairs

For the troop’s award night, Lennart sets out 9 rows of chairs with 9 chairs in each row. How many chairs does he set out?

Solution

The count is 9 \times 9. Ten rows of 9 would be 10 \times 9 = 90, so take one row of 9 away:

9 \times 9 = (10 \times 9) - (1 \times 9) = 90 - 9

Subtracting 9 from 90 crosses down past 80. Take away 10 instead, which gives 80, then give back the 1 that was taken too many, which gives 81. So 9 \times 9 = 81.

Lennart sets out 81 chairs. Check: split the 9 rows as 5 + 4, (5 \times 9) + (4 \times 9) = 45 + 36 = 81.

Example 3

Tent stakes

Malin packs 8 tent bags with 9 tent stakes in each bag. How many tent stakes does she pack?

Solution

Eight bags of 9 is 8 \times 9. Double 9 three times, as in the picture in Part 2:

9 \;\to\; 18 \;\to\; 36 \;\to\; 72

The first doubling is 9 + 9 = 18, two bags. The second is 18 + 18: the tens give 20 and the ones give 16, so 36, four bags. The third is 36 + 36: the tens give 60 and the ones give 12, so 72, eight bags. The associative property makes the chain correct, since 8 \times 9 = 2 \times \bigl(2 \times (2 \times 9)\bigr).

Malin packs 72 tent stakes.

Check with the tens: 10 bags would hold 90, and 8 bags is two bags fewer, so 90 - 18 = 72. That is the distributive property with 8 written as 10 - 2.

Example 4

Eight patrols

The troop has 8 patrols with 8 scouts in each patrol. How many scouts are in the troop?

Solution

The count is 8 \times 8. Double the 8 three times:

8 \;\to\; 16 \;\to\; 32 \;\to\; 64

The last step is 32 + 32, which is 60 and 4, so 64. Grouped the way the associative property allows,

8 \times 8 = (2 \times 4) \times 8 = 2 \times (4 \times 8) = 2 \times 32 = 64

so an eight fact is a four fact doubled, here double 4 \times 8 = 32.

The troop has 64 scouts. Check: split the patrols as 5 + 3, (5 \times 8) + (3 \times 8) = 40 + 24 = 64.

Example 5

Cones for relay practice

Lennart sets out cones in 7 rows with 7 cones in each row. How many cones does he use?

Solution

The count is 7 \times 7. Split the 7 cones in each row as 5 + 2, which is the cut after the fifth column in Part 3. The distributive property gives

\begin{aligned} 7 \times 7 &= (7 \times 5) + (7 \times 2) \\ &= 35 + 14 = 49 \end{aligned}

Adding 35 + 14: the tens give 30 + 10 = 40 and the ones give 5 + 4 = 9, so 49.

Lennart uses 49 cones. Check by one more group from a six fact: six rows of 7 are 6 \times 7 = 42, and the seventh row adds 7, so 42 + 7 = 49.

Example 6

Seven teams of eight

Isaure’s relay race has 7 teams with 8 runners on each team. Find the number of runners two ways.

Solution

The count is 7 \times 8.

Split the seven. Split the 7 teams as 5 + 2. Five teams of 8 is a five fact, and two teams of 8 is a two fact. The distributive property gives

7 \times 8 = (5 \times 8) + (2 \times 8) = 40 + 16 = 56

One more team. Six teams of 8 is the six fact 6 \times 8 = 48, and the seventh team adds one more group of 8. The distributive property, with 7 split as 6 + 1, gives

7 \times 8 = (6 \times 8) + (1 \times 8) = 48 + 8 = 56

Both routes give 56, so the race has 56 runners.

Example 7

Sharing granola bars

The troop has 72 granola bars to share equally among its 8 patrols. How many bars does each patrol get?

Solution

Each patrol’s share is the missing factor in

8 \times \square = 72

Start from a ten fact: 8 \times 10 = 80. That is 8 too many, since 80 - 72 = 8, which is one group of 8. One group fewer than ten groups is nine groups, so \square = 9.

Check by doubling: 9 \to 18 \to 36 \to 72, so 8 \times 9 = 72. Each patrol gets 9 granola bars.

Example 8

Enough bibs?

For the relay race, 7 teams of 9 runners each sign up. Malin has 60 runner bibs. Are there enough bibs for every runner? If not, how many more are needed?

Solution

The number of runners is 7 \times 9. Two routes:

  • Sevens: split the 7 teams as 5 + 2. Five teams of 9 are 45 and two teams are 18, so (5 \times 9) + (2 \times 9) = 45 + 18 = 63.
  • Nines: by the commutative property 7 \times 9 = 9 \times 7, and Example 1 found 9 \times 7 = 70 - 7 = 63.

Both give 63 runners. That is more than 60, so the bibs are not enough. The number still needed is 63 - 60 = 3.

Malin needs 3 more bibs.

Boundaries

  • The group taken away is a whole group of the other factor. 9 \times 7 is 70 - 7, one row of 7. Taking away 1, or taking away 9, does not remove a row.
  • Ten take away one gives nine, and only nine. The move 10 \times n - n gives 9 \times n. Other near-ten factors take away more groups: 8 \times n is 10 \times n - 2 \times n, two groups.
  • Doubling three times gives eight because 2 \times 2 \times 2 = 8. Doubling once gives two groups, twice gives four, three times gives eight. A fourth doubling gives sixteen groups, which is past the facts to know by heart.
  • The parts of a split must add up to the factor. 7 = 5 + 2, so the pieces of the array fill it exactly. Parts that add to 6 count only six columns.
  • A backward question needs an exact fit. \square \times 8 = 70 has no whole number answer, because 8 \times 8 = 64 and 8 \times 9 = 72 jump over 70.
  • Whole groups and factors from 0 to 10. The moves still hold at zero (9 \times 0 = 0 - 0 = 0) and past ten, but the facts to know by heart stop at 10 \times 10.

Where this goes next

With this lesson the table is complete, and every fact also answers a division question: 8 \times \square = 72 is 72 \div 8, and Division facts builds division on that link. Patterns in the multiplication table looks at the finished table as a whole: the digit pattern down the nines, rows that are doubles of other rows, and the squares along the diagonal. A fact like 9 \times 7 grows into 9 \times 70 in Multiplying by tens and hundreds. Later, changing a product by doubling one factor and halving the other becomes a strategy of its own in Doubling, halving and quick products. All of these sit under Multiplication facts.

Exercises

Exercises 1 to 5 go with Part 1, 6 to 9 with Part 2, 10 to 13 with Part 3, and 14 to 21 with Part 4. The reasoning group draws on all four.

Part 1: nines

  1. Find 9 \times 4 by taking one group of 4 away from 10 \times 4.
  2. Fill in the boxes: 9 \times 6 = (10 \times 6) - \square, which is 60 - \square, which is \square.
  3. A relay race has 9 teams with 3 runners on each team. How many runners are there?
  4. Find 9 \times 5 two ways: as a ten fact take away one group, and as a five fact.
  5. Find 9 \times 2 two ways: as 20 take away one group of 2, and by doubling 9.

Part 2: eights

  1. Find 8 \times 6 by doubling 6 three times.
  2. Eight relay teams have 3 runners each. Find the number of runners by doubling.
  3. Find 8 \times 5 by doubling 5 three times, then check with a five fact.
  4. Fill in the boxes: 8 \times 4 = 2 \times (4 \times 4) = 2 \times \square = \square.

Part 3: sevens

  1. Find 7 \times 6 by splitting the 7 as 5 + 2.
  2. Malin’s troop has 7 patrols with 4 scouts in each. How many scouts is that?
  3. Fill in the boxes: 7 \times 10 = (5 \times 10) + (2 \times 10) = \square + \square = \square.
  4. Find 7 \times 5 by splitting the 7 as 5 + 2, then check with a five fact.

Part 4: the whole table

  1. Fill in the missing factors: 9 \times \square = 27, 8 \times \square = 32 and 7 \times \square = 42.
  2. Lennart puts 48 runners into teams of 8. How many teams are there?
  3. Isaure sews 54 badges onto sashes, 9 badges on each sash. How many sashes does she use?
  4. The troop has 7 patrols of 8 scouts and 9 leaders. How many people is that in all?
  5. Which is larger, 8 \times 6 or 7 \times 7, and by how much?
  6. Write the nine row, 9 \times 1 to 9 \times 10.
  7. A relay race has 9 teams of 4 runners. Malin has 80 bibs. How many bibs are left over after every runner has one?
  8. The troop has 70 scouts. Can they be split into patrols of 7 with none left over? Of 8? Of 9? Give the number of patrols where it works.

Reasoning

  1. Explain, with an array, why 9 \times 8 is the same as 80 - 8. Name the property that makes it true.
  2. Explain why doubling a number three times gives eight groups of that number. Name the property that makes it true.
  3. Explain why, once the facts for 0, 1, 2, 3, 4, 5, 6 and 10 are known, exactly six facts of the table are left.
  4. Is every product with a factor of 8 also a product with a factor of 4? Explain, and give an example.
Answers
  1. 36. 10 \times 4 = 40, and taking away one group of 4 leaves 40 - 4 = 36.
  2. The boxes are 6, 6 and 54: 60 - 6 = 54.
  3. 27 runners. 9 \times 3 = (10 \times 3) - 3 = 30 - 3 = 27.
  4. 45 both ways. (10 \times 5) - 5 = 50 - 5 = 45, and the five fact 9 \times 5 = 5 \times 9 = 45.
  5. 18 both ways. 20 - 2 = 18, and 9 + 9 = 18.
  6. 48. 6 \to 12 \to 24 \to 48.
  7. 24 runners. 8 \times 3: 3 \to 6 \to 12 \to 24.
  8. 40. 5 \to 10 \to 20 \to 40, and the five fact 8 \times 5 = 5 \times 8 = 40 agrees.
  9. The boxes are 16 and 32: 4 \times 4 = 16 and 2 \times 16 = 32.
  10. 42. (5 \times 6) + (2 \times 6) = 30 + 12 = 42.
  11. 28 scouts. 7 \times 4 = (5 \times 4) + (2 \times 4) = 20 + 8 = 28.
  12. The boxes are 50, 20 and 70: 50 + 20 = 70.
  13. 35. (5 \times 5) + (2 \times 5) = 25 + 10 = 35, and the five fact 7 \times 5 = 35 agrees.
  14. 3, 4 and 6. 9 \times 3 = 30 - 3 = 27, 8 \times 4 = 32 (double 4 three times: 8, 16, 32) and 7 \times 6 = 30 + 12 = 42.
  15. 6 teams. \square \times 8 = 48, and 6 \times 8 = 48 (double 6 three times: 12, 24, 48).
  16. 6 sashes. \square \times 9 = 54, and 6 \times 9 = 54, since 9 \times 6 = 60 - 6 = 54.
  17. 65 people. 7 \times 8 = 56 scouts, and 56 + 9 = 65.
  18. 7 \times 7, by 1. 8 \times 6 = 48 and 7 \times 7 = 49, and 49 - 48 = 1.
  19. 9, 18, 27, 36, 45, 54, 63, 72, 81, 90. Each is one more group of 9 than the one before, and each is the ten fact take away one group: for example 9 \times 6 = 60 - 6 = 54.
  20. 44 bibs. 9 \times 4 = 40 - 4 = 36 runners, and 80 - 36 = 44.
  21. Patrols of 7: yes, 10 patrols, since 10 \times 7 = 70. Patrols of 8: no, since 8 \times 8 = 64 and 8 \times 9 = 72 jump over 70, leaving 6 scouts over. Patrols of 9: no, since 9 \times 7 = 63 and 9 \times 8 = 72 jump over 70, leaving 7 scouts over.
  22. Draw 10 rows of 8, which is 10 \times 8 = 80 dots, and strike out the last row. The row struck out is 1 \times 8 = 8 dots, and what is left is 9 rows of 8. So 9 \times 8 = 80 - 8 = 72. This is the distributive property with 9 written as 10 - 1: (10 - 1) \times 8 = (10 \times 8) - (1 \times 8).
  23. Doubling a number once gives two groups of it. Doubling again gives two sets of two groups, which is four groups. Doubling a third time gives two sets of four groups, which is eight groups. In symbols, 2 \times \bigl(2 \times (2 \times n)\bigr), and the associative property says this equals (2 \times 2 \times 2) \times n = 8 \times n. For example, 2 \to 4 \to 8 \to 16, and 8 \times 2 = 16.
  24. The factors left to deal with are 7, 8 and 9, since every other factor from 0 to 10 is already known. A fact not yet known must have both factors from 7, 8 and 9, or it would contain a known factor. By the commutative property each pair counts once in either order, so the pairs are 7 \times 7, 7 \times 8, 7 \times 9, 8 \times 8, 8 \times 9 and 9 \times 9: six facts.
  25. Yes. Eight is 4 \times 2, so by the associative property 8 \times n = (4 \times 2) \times n = 4 \times (2 \times n), which is a product with a factor of 4. For example, 8 \times 3 = 24 and 4 \times 6 = 24, where 6 = 2 \times 3.
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