math.wiki
Fractions, ratio and percent › Fractions › Fraction of a quantity › Finding the whole when only a fraction of it is known
Open on the map
Math 6

Finding the whole when only a fraction of it is known

You know how much has been done, and what fraction of the job that is. How big is the whole job?

Where you are 3 in Fraction of a quantity

When you reach for it

A class is painting a mural on the school wall, one section at a time. Every question about it has three numbers in it: the whole job, a part of the job, and the fraction of the whole that the part is. They are tied together by one multiplication:

\text{part} = \text{fraction} \times \text{whole}

When you know the whole and the fraction, you multiply, as in finding a fraction of a number: \displaystyle \frac{3}{4} of a 16 square meter mural is 12 square meters.

This lesson runs the other way. You can see the part, and you are told what fraction of the whole it is, but the whole is hidden. Beatriz has painted 12 square meters, and that is \displaystyle \frac{3}{4} of the mural. How big is the mural? Reach for this move whenever an amount comes with the words “which is ... of the whole”, “that is ... of what we need”, or “so far we have done ...”.

The procedure

A tape diagram

Draw the whole mural as a long bar, a tape. The fraction \displaystyle \frac{3}{4} says the mural is cut into 4 equal pieces and the part fills 3 of them, so cut the tape into 4 equal pieces and shade 3. The 12 square meters go over the shaded pieces.

4
4
4
4
12\ \text{m}^2
\text{whole mural: } 16\ \text{m}^2
Figure 1Twelve square meters fill 3 of the 4 equal pieces, so one piece is 4 square meters and the whole mural is 16.

Now read the tape. Three equal pieces hold 12 square meters, so one piece holds 12 \div 3 = 4. The pieces are equal, which is what lets you share the 12 evenly. The whole is 4 of those pieces, so it is 4 \times 4 = 16 square meters.

That is the whole idea: the numerator tells you how many pieces the part fills, so dividing by it gives one piece; the denominator tells you how many pieces make the whole, so multiplying by it gives the whole.

Dividing by the fraction

The multiplication above has the whole as its missing factor:

12 = \frac{3}{4} \times \text{whole}

A missing factor is found by division, because division undoes multiplication. So

\text{whole} = 12 \div \frac{3}{4} = 12 \times \frac{4}{3} = 16

Dividing by \displaystyle \frac{3}{4} is multiplying by its reciprocal \displaystyle \frac{4}{3}, as dividing by multiplying by the reciprocal shows, and why flipping works explains. The tape shows the same two moves: multiplying by \displaystyle \frac{4}{3} divides by 3 and multiplies by 4, which is “find one piece, then build the whole”. The tape is the picture and the division is the shortcut; they always agree.

In general, if a part p is \displaystyle \frac{a}{b} of the whole, then

\text{whole} = p \div \frac{a}{b} = p \times \frac{b}{a}

When the part is a mixed number, write it as an improper fraction first, as in dividing mixed numbers.

Checking by multiplying back

The answer can always be tested, because the forward direction is easy. Take the fraction of your whole and see whether it gives the part back:

\frac{3}{4} \times 16 = 12

It does, so 16 square meters is right. A quick size check helps too. When the fraction is less than 1, the part is smaller than the whole, so the whole must come out bigger than the part. An answer smaller than the part is wrong before you multiply anything.

Worked examples

Example 1

A unit fraction

Soren paints the first section of the mural, 9 square meters. That is \displaystyle \frac{1}{5} of the mural. How big is the mural?

Solution

A tape cut into 5 equal pieces has the 9 square meters in 1 piece. The whole is 5 such pieces, so it is 5 \times 9 = 45 square meters.

Dividing gives the same: \displaystyle 9 \div \frac{1}{5} = 9 \times 5 = 45. With a unit fraction, dividing by the numerator 1 changes nothing, so only the multiplying is left.

Check. \displaystyle \frac{1}{5} \times 45 = 9.

Example 2

Counting tins

Ola’s group has used 15 tins of paint, which is \displaystyle \frac{5}{8} of the paint the whole mural needs. How many tins does the mural need?

Solution

On a tape of 8 equal pieces, the 15 tins fill 5. One piece is 15 \div 5 = 3 tins, and the whole is 8 \times 3 = 24 tins.

By division:

15 \div \frac{5}{8} = 15 \times \frac{8}{5} = \frac{120}{5} = 24

The mural needs 24 tins. Check. \displaystyle \frac{5}{8} \times 24 = \frac{120}{8} = 15.

Example 3

When the part is itself a fraction

Nia uses \displaystyle \frac{3}{4} of a tin of blue on the sky. That is \displaystyle \frac{3}{10} of all the paint the mural needs. How much paint does the mural need?

Solution

The tape still works. Cut it into 10 equal pieces and shade 3; those 3 hold \displaystyle \frac{3}{4} of a tin, so one piece holds \displaystyle \frac{1}{4} of a tin.

\tfrac{1}{4}
\tfrac{1}{4}
\tfrac{1}{4}
\tfrac{3}{4}\ \text{tin}
10 \times \tfrac{1}{4} = 2\tfrac{1}{2}\ \text{tins}
Figure 2Example 3. Three quarters of a tin fills 3 of 10 pieces, so each piece is \displaystyle \frac{1}{4} of a tin.

The whole is 10 pieces, \displaystyle 10 \times \frac{1}{4} = \frac{10}{4} = 2\frac{1}{2} tins. By division:

\frac{3}{4} \div \frac{3}{10} = \frac{3}{4} \times \frac{10}{3} = \frac{30}{12} = \frac{5}{2}

The mural needs \displaystyle 2\frac{1}{2} tins. A whole does not have to be a whole number.

Check. \displaystyle \frac{3}{10} \times \frac{5}{2} = \frac{15}{20} = \frac{3}{4}.

Example 4

A mixed number

Rahim’s section is \displaystyle 7\frac{1}{2} square meters, which is \displaystyle \frac{5}{12} of the mural. Find the area of the mural.

Solution

Write the mixed number as an improper fraction, \displaystyle 7\frac{1}{2} = \frac{15}{2}, then divide:

\frac{15}{2} \div \frac{5}{12} = \frac{15}{2} \times \frac{12}{5} = \frac{180}{10} = 18

The tape agrees: 5 of 12 pieces hold \displaystyle \frac{15}{2}, so one piece holds \displaystyle \frac{15}{2} \div 5 = \frac{3}{2}, and 12 pieces hold \displaystyle 12 \times \frac{3}{2} = 18. The mural is 18 square meters.

Check. \displaystyle \frac{5}{12} \times 18 = \frac{90}{12} = \frac{15}{2} = 7\frac{1}{2}.

Example 5

The fraction that goes with the number

By the end of Monday, \displaystyle \frac{3}{8} of the mural is painted, and 20 square meters are still to paint. How big is the mural, and how much is painted?

Solution

The 20 square meters are the part not painted, so they do not go with \displaystyle \frac{3}{8}. The unpainted part is \displaystyle 1 - \frac{3}{8} = \frac{5}{8} of the mural, and that is the fraction that belongs with 20.

4
4
4
4
4
\text{painted}
20\ \text{m}^2\ \text{left}
32\ \text{m}^2
Figure 3Example 5. The 20 square meters still to paint go with the 5 unshaded pieces, not the 3 shaded ones.

Five pieces hold 20, so one piece is 4 and the mural is 8 \times 4 = 32 square meters. By division, \displaystyle 20 \div \frac{5}{8} = 20 \times \frac{8}{5} = 32. The painted part is \displaystyle \frac{3}{8} \times 32 = 12 square meters.

Check. 12 + 20 = 32, and \displaystyle \frac{5}{8} \times 32 = 20.

Example 6

Two days’ work together

Elena paints \displaystyle \frac{1}{4} of the mural on Tuesday and Soren paints \displaystyle \frac{1}{6} of it on Wednesday. Together that is 15 square meters. How big is the mural?

Solution

Neither day’s area is known alone, but their total is, so find the fraction the total is. Over the common denominator 12:

\frac{1}{4} + \frac{1}{6} = \frac{3}{12} + \frac{2}{12} = \frac{5}{12}

So 15 square meters is \displaystyle \frac{5}{12} of the mural, and the mural is \displaystyle 15 \div \frac{5}{12} = 15 \times \frac{12}{5} = 36 square meters.

Check. Tuesday is \displaystyle \frac{1}{4} \times 36 = 9 and Wednesday is \displaystyle \frac{1}{6} \times 36 = 6, and 9 + 6 = 15.

Example 7

Working back through two fractions

The sky takes up 8 square meters. It is \displaystyle \frac{2}{3} of the top panel, and the top panel is \displaystyle \frac{2}{5} of the mural. How big is the mural?

Solution

Work back one step at a time. The sky is \displaystyle \frac{2}{3} of the top panel, so the panel is \displaystyle 8 \div \frac{2}{3} = 8 \times \frac{3}{2} = 12 square meters. The panel is \displaystyle \frac{2}{5} of the mural, so the mural is \displaystyle 12 \div \frac{2}{5} = 12 \times \frac{5}{2} = 30 square meters.

It can also be done in one step. The sky is \displaystyle \frac{2}{3} of \displaystyle \frac{2}{5} of the mural, which is \displaystyle \frac{2}{3} \times \frac{2}{5} = \frac{4}{15} of it, as in a fraction of a fraction. Then \displaystyle 8 \div \frac{4}{15} = 8 \times \frac{15}{4} = 30. Both routes give 30 square meters.

Check. \displaystyle \frac{4}{15} \times 30 = 8.

Boundaries

The fraction must belong to the number you were given. If the fraction describes one part and the number describes another, as in Example 5, find the fraction that goes with the number first.

The fraction must be of the whole you want. In Example 7 the sky is \displaystyle \frac{2}{3} of a panel, not of the mural, so one division gives the panel and a second gives the mural.

The pieces must be equal. A fraction means equal shares, which is why one piece can be found by sharing the part evenly. When paint and area are mixed in one problem, the move also needs the paint to go on evenly, so that a fraction of the area uses the same fraction of the tins.

The fraction cannot be 0. “No part of the mural is 5 square meters” makes no sense, and there is no dividing by 0.

A fraction bigger than 1 still divides, but the word “part” no longer fits. If 15 tins is \displaystyle \frac{5}{4} of what is needed, then \displaystyle 15 \div \frac{5}{4} = 12 tins are needed, fewer than you have. The amount is more than the whole, so the whole comes out smaller.

Where this goes next

Finding the whole is the “how much in one whole” meaning of division, the one in sharing into equal parts. The next lesson, word problems that divide fractions, mixes it with the “how many fit” meaning and asks you to tell them apart. A tape cut into equal pieces is also the main tool of tape diagrams for ratios. Later, the same backwards move with hundredths in place of other fractions becomes finding the whole from a part and a percent.

Exercises

Tape diagrams

Draw a tape diagram for each, then find the whole.

  1. Beatriz paints 7 square meters, which is \displaystyle \frac{1}{6} of the mural. How big is the mural?
  2. The class has used 18 tins of paint, which is \displaystyle \frac{3}{5} of the paint the mural needs. How many tins does the mural need?
  3. Ola’s border is 20 square meters, which is \displaystyle \frac{4}{9} of the mural. How big is the mural?
  4. Rahim has painted 14 square meters, which is \displaystyle \frac{7}{10} of the mural. How big is the mural?

Dividing by the fraction

Find the whole by dividing, then check by multiplying back.

  1. 24 square meters is \displaystyle \frac{6}{7} of a mural. Find the area of the mural.
  2. Nia uses \displaystyle \frac{2}{3} of a tin of yellow, which is \displaystyle \frac{1}{9} of all the paint. How much paint is there?
  3. Elena uses \displaystyle \frac{5}{6} of a tin of green, which is \displaystyle \frac{5}{8} of all the green the mural needs. How much green does it need?
  4. Soren’s section is \displaystyle 3\frac{3}{4} square meters, which is \displaystyle \frac{3}{8} of the mural. Find the area of the mural.
  5. The class has used \displaystyle 6\frac{2}{3} tins, which is \displaystyle \frac{5}{6} of the paint the mural needs. How many tins does it need?
  6. Beatriz’s sunflower is \displaystyle 4\frac{1}{2} square meters, which is \displaystyle \frac{9}{20} of the mural. Find the area of the mural.

Which fraction goes with the number

  1. \displaystyle \frac{2}{7} of the mural is painted, and 25 square meters are still to paint. How big is the mural?
  2. After the first day, \displaystyle \frac{5}{12} of the mural is painted and 21 square meters are left. How big is the mural, and how much was painted on the first day?
  3. Elena has used \displaystyle \frac{3}{5} of her tins and has 8 tins left. How many did she start with?

Two steps

  1. Soren paints \displaystyle \frac{1}{3} of the mural and Nia paints \displaystyle \frac{1}{4} of it. Together they paint 28 square meters. How big is the mural?
  2. A tree takes up 9 square meters, which is \displaystyle \frac{3}{5} of the left panel. The left panel is \displaystyle \frac{1}{4} of the mural. How big is the mural?
  3. Beatriz paints \displaystyle \frac{1}{2} of the mural, Ola paints \displaystyle \frac{1}{3}, and Rahim paints the remaining 7 square meters. How big is the mural?
  4. Rahim has painted \displaystyle \frac{3}{8} of the mural with 6 tins. Paint goes on evenly. How many more tins does he need to finish?
  5. The class bought 21 tins of paint, which turns out to be \displaystyle \frac{7}{6} of the paint the mural needs. How many tins does the mural need, and how many will be left over?

Reasoning

  1. Beatriz says the 10 square meters finished so far are \displaystyle \frac{2}{5} of the mural. Ola says the 6 square meter border is \displaystyle \frac{1}{4} of the same mural. Can both be right? Explain.
  2. Explain, using a tape diagram, why \displaystyle 12 \div \frac{3}{4} can be worked out as “divide by 3, then multiply by 4”.
  3. Nia says that 12 square meters is \displaystyle \frac{3}{5} of the mural, so the mural is 8 square meters. Without working out the answer, explain how you know she is wrong.
  4. Explain why multiplying the fraction by your answer checks a “find the whole” problem.
  5. Write a mural problem whose answer is \displaystyle 12 \div \frac{2}{3}, then solve it.
Answers
  1. 42 square meters. One piece is 7, and 6 pieces make 6 \times 7 = 42.
  2. 30 tins. One piece is 18 \div 3 = 6, and 5 \times 6 = 30.
  3. 45 square meters. One piece is 20 \div 4 = 5, and 9 \times 5 = 45.
  4. 20 square meters. One piece is 14 \div 7 = 2, and 10 \times 2 = 20.
  5. 28 square meters. \displaystyle 24 \times \frac{7}{6} = 28; check \displaystyle \frac{6}{7} \times 28 = 24.
  6. 6 tins. \displaystyle \frac{2}{3} \times 9 = 6; check \displaystyle \frac{1}{9} \times 6 = \frac{2}{3}.
  7. \displaystyle 1\frac{1}{3} tins. \displaystyle \frac{5}{6} \times \frac{8}{5} = \frac{8}{6} = \frac{4}{3}; check \displaystyle \frac{5}{8} \times \frac{4}{3} = \frac{20}{24} = \frac{5}{6}.
  8. 10 square meters. \displaystyle \frac{15}{4} \times \frac{8}{3} = \frac{120}{12} = 10; check \displaystyle \frac{3}{8} \times 10 = \frac{15}{4}.
  9. 8 tins. \displaystyle \frac{20}{3} \times \frac{6}{5} = \frac{120}{15} = 8; check \displaystyle \frac{5}{6} \times 8 = \frac{20}{3}.
  10. 10 square meters. \displaystyle \frac{9}{2} \times \frac{20}{9} = \frac{180}{18} = 10; check \displaystyle \frac{9}{20} \times 10 = \frac{9}{2}.
  11. 35 square meters. The 25 goes with \displaystyle 1 - \frac{2}{7} = \frac{5}{7}, and \displaystyle 25 \times \frac{7}{5} = 35.
  12. 36 square meters, of which 15 were painted. The 21 goes with \displaystyle \frac{7}{12}, so the whole is \displaystyle 21 \times \frac{12}{7} = 36, and \displaystyle \frac{5}{12} \times 36 = 15.
  13. 20 tins. The 8 left are \displaystyle \frac{2}{5} of her tins, and \displaystyle 8 \times \frac{5}{2} = 20.
  14. 48 square meters. \displaystyle \frac{1}{3} + \frac{1}{4} = \frac{7}{12}, and \displaystyle 28 \times \frac{12}{7} = 48.
  15. 60 square meters. The panel is \displaystyle 9 \times \frac{5}{3} = 15, and the mural is 15 \times 4 = 60.
  16. 42 square meters. Rahim’s part is \displaystyle 1 - \frac{1}{2} - \frac{1}{3} = \frac{1}{6}, and 7 \times 6 = 42.
  17. 10 more tins. The whole mural takes \displaystyle 6 \div \frac{3}{8} = 16 tins, and 16 - 6 = 10.
  18. The mural needs 18 tins, and 3 will be left over. \displaystyle 21 \div \frac{7}{6} = 21 \times \frac{6}{7} = 18, and 21 - 18 = 3; check \displaystyle \frac{7}{6} \times 18 = 21. The fraction is more than 1, so the whole comes out smaller than the 21 tins bought.
  19. No. Beatriz’s numbers give \displaystyle 10 \div \frac{2}{5} = 25 square meters and Ola’s give \displaystyle 6 \div \frac{1}{4} = 24 square meters. One mural cannot have two areas.
  20. On a tape of 4 equal pieces with 12 over 3 of them, dividing by 3 gives one piece, 4, and multiplying by 4 gives the 4 pieces of the whole, 16. Multiplying by \displaystyle \frac{4}{3} does exactly these two things.
  21. \displaystyle \frac{3}{5} is less than 1, so 12 square meters is less than the whole mural. The mural must be bigger than 12, and 8 is smaller.
  22. The problem says the part equals the fraction times the whole. If the fraction times your answer gives the part back, your answer satisfies the problem.
  23. For example: Ola has painted 12 square meters, which is \displaystyle \frac{2}{3} of the mural. How big is the mural? \displaystyle 12 \times \frac{3}{2} = 18 square meters.
kg1128 · updated 2026-10-12 · CC-BY-SA-4.0