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Math 7 · 7.RP.A.1

Unit rates when the amounts are fractions

You walked part of a mile in part of an hour. How far is that for one whole hour?

Where you are 5 in Rate and unit rate

When you reach for it

A unit rate says how much of one quantity goes with exactly one of another: miles in one hour, cups of honey in one batch, how much of a lawn is mowed in one hour. When both amounts are whole numbers, finding it is one division: 6 miles in 2 hours is 6 \div 2 = 3 miles per hour.

Real measurements are rarely that tidy. A walk of \displaystyle \frac{2}{3} of a mile takes a quarter of an hour. A painter covers \displaystyle \frac{3}{8} of a fence in \displaystyle \frac{3}{4} of an hour. A three-quarter batch of granola uses \displaystyle \frac{1}{2} cup of honey. Neither amount is “one” of anything, and you cannot count up in steps of 1 to reach a whole hour. Reach for this skill whenever both sides of a rate are fractions or mixed numbers and you want the amount that goes with one.

The answer is still a division, and the rate can be written as a single fraction whose top and bottom are themselves fractions, such as

\dfrac{\frac{2}{3}}{\frac{1}{4}}

This lesson shows why that division gives the amount per one, how to carry it out, and how to use the result. It is taught in two parts. Part 1 builds the idea with fractions of a mile and of an hour, and treats fractions built out of fractions as numbers in their own right. Part 2 brings in mixed numbers, jobs and areas, ingredients per batch, and comparing two rates.

The procedure

Part 1: from a fraction of an hour to a whole hour

A unit fraction of an hour. Femi walks \displaystyle \frac{2}{3} of a mile in \displaystyle \frac{1}{4} of an hour, at a steady pace. Lay the hours and the miles side by side on a double number line, where points that sit one above the other go together.

0
0
\displaystyle \frac{1}{4}
\displaystyle \frac{2}{3}
\displaystyle \frac{1}{2}
\displaystyle \frac{4}{3}
\displaystyle \frac{3}{4}
2
1
\displaystyle \frac{8}{3}
\text{hours}
\text{miles}
Figure 1Each quarter-hour adds the same \displaystyle \frac{2}{3} of a mile, so four quarter-hours add four times as much.

An hour is four quarter-hours. At a steady pace every quarter-hour adds the same distance, \displaystyle \frac{2}{3} of a mile, so one hour covers four times as much:

4 \times \frac{2}{3} = \frac{8}{3} = 2\frac{2}{3}

Femi walks at \displaystyle 2\frac{2}{3} miles per hour. Multiplying by 4 was right because 4 is the number of quarter-hours in an hour, and that is the same thing as dividing by \displaystyle \frac{1}{4}, since \displaystyle \frac{1}{4} fits into 1 exactly four times:

\frac{2}{3} \div \frac{1}{4} = \frac{2}{3} \times 4 = \frac{8}{3}

Any fraction of an hour. Hana swims \displaystyle \frac{9}{10} of a mile in \displaystyle \frac{3}{5} of an hour. Now the time is three fifths of an hour, not one fifth, so reach one hour in two moves.

0
0
\displaystyle \frac{1}{5}
\displaystyle \frac{3}{10}
\displaystyle \frac{2}{5}
\displaystyle \frac{3}{5}
\displaystyle \frac{3}{5}
\displaystyle \frac{9}{10}
\displaystyle \frac{4}{5}
\displaystyle \frac{6}{5}
1
\displaystyle \frac{3}{2}
\text{hours}
\text{miles}
Figure 2The shaded stretch is what was measured. Split it into three equal fifths of an hour, then count five of them.

Down to one part. \displaystyle \frac{3}{5} of an hour is three fifths. At a steady pace each fifth carries the same distance, so one fifth of an hour carries a third of the distance:

\frac{9}{10} \div 3 = \frac{9}{30} = \frac{3}{10}

Up to a whole. An hour is five fifths, so it carries five times that:

5 \times \frac{3}{10} = \frac{15}{10} = \frac{3}{2}

Hana swims at \displaystyle 1\frac{1}{2} miles per hour. The two moves were “divide by 3, then multiply by 5”, which together is “multiply by \displaystyle \frac{5}{3}”, and \displaystyle \frac{5}{3} is the reciprocal of the time, \displaystyle \frac{3}{5}. So the two moves are exactly dividing by multiplying by the reciprocal:

\frac{9}{10} \div \frac{3}{5} = \frac{9}{10} \times \frac{5}{3} = \frac{45}{30} = \frac{3}{2}

The same two moves work for any fraction of an hour \displaystyle \frac{c}{d}. Divide by c to get the amount for \displaystyle \frac{1}{d} of an hour, then multiply by d to get the amount for \displaystyle \frac{d}{d} = 1 hour. Together that is multiplying by \displaystyle \frac{d}{c}, which is dividing by \displaystyle \frac{c}{d}. So in every case

\text{unit rate} = \text{first amount} \div \text{second amount}

where the second amount is the one you want exactly one of.

Fractions built out of fractions. A rate is often written with a fraction bar: 6 miles in 2 hours is \displaystyle \frac{6}{2} miles per hour. Written the same way, Hana’s rate is

\dfrac{\frac{9}{10}}{\frac{3}{5}}\ \text{miles per hour}

A fraction whose top or bottom, or both, contains a fraction is called a complex fraction. “Complex” here means built from parts, not difficult. Its long bar means division, exactly as in any fraction, so a complex fraction is simplified by carrying out that division. A second way is often quicker: multiply the top and the bottom by one number chosen to clear both small denominators. Here 10 works, since it is a multiple of both 10 and 5:

\dfrac{\frac{9}{10}}{\frac{3}{5}} = \dfrac{\frac{9}{10} \times 10}{\frac{3}{5} \times 10} = \frac{9}{6} = \frac{3}{2}

This is allowed because multiplying top and bottom by 10 multiplies the whole fraction by \displaystyle \frac{10}{10}, which is 1, and multiplying by 1 changes nothing. It also makes sense as a rate: 9 miles in 6 hours is ten times as far in ten times as long, the same pace as \displaystyle \frac{9}{10} of a mile in \displaystyle \frac{3}{5} of an hour.

Two unit rates from one pair. The pair “\displaystyle \frac{9}{10} of a mile with \displaystyle \frac{3}{5} of an hour” answers two questions. Miles for one hour is miles divided by hours, which gave \displaystyle \frac{3}{2}. Hours for one mile is hours divided by miles:

\frac{3}{5} \div \frac{9}{10} = \frac{3}{5} \times \frac{10}{9} = \frac{30}{45} = \frac{2}{3}

Hana takes \displaystyle \frac{2}{3} of an hour, which is 40 minutes, for each mile. The two unit rates are reciprocals of each other, \displaystyle \frac{3}{2} \times \frac{2}{3} = 1, because each is the other’s division done the other way round. The question decides which one you want: “how far in an hour?” asks for miles per hour, and “how long for a mile?” asks for hours per mile.

Part 2: mixed numbers, jobs, batches and comparisons

Mixed numbers become single fractions first. \displaystyle 2\frac{1}{2} means \displaystyle 2 + \frac{1}{2}. Division acts on the whole amount, so first rewrite it as an improper fraction, \displaystyle \frac{5}{2}, and then divide exactly as in Part 1.

A whole job as the unit. When someone paints part of a fence or mows part of a lawn, the natural “one” is the whole fence or the whole lawn. Dividing the fraction of the job done by the time taken gives the fraction of the job done per hour, and dividing the other way gives the hours for one whole job. The job can also be measured as an area, in square meters or acres, and then the rate is square meters or acres per hour. Example 5 works one through with a picture.

Per batch. An ingredient works the same way. Cups divided by batches gives cups per batch. Batches divided by cups gives batches per cup, which says how many batches fit into the amount you have.

Comparing two rates. Two walkers who cover different distances in different times cannot be compared by either number alone: the one who went further may also have taken longer. Turn each pair into a unit rate with the same “per”, then compare those. If you compare hours per mile, or hours per job, the smaller number belongs to the faster one, since it needs less time for the same amount.

Keep the fractions exact. Fractions such as \displaystyle \frac{1}{3} and \displaystyle \frac{1}{6} have decimals that never end. Rounding them before dividing gives a unit rate that is slightly off, and the error grows when the rate is used to predict a larger amount (Example 8). Divide the fractions exactly and round only at the end, if at all.

Worked examples

Examples 1 to 3 belong to Part 1. Examples 4 to 8 belong to Part 2.

Example 1

Swimming, and both unit rates

Rafael swims \displaystyle \frac{3}{5} of a mile in \displaystyle \frac{1}{3} of an hour at a steady pace. (a) How many miles does he swim per hour? (b) How long does he take per mile?

Solution

(a) Miles per hour means miles divided by hours. Dividing by \displaystyle \frac{1}{3} is multiplying by 3, because three thirds of an hour make one hour:

\frac{3}{5} \div \frac{1}{3} = \frac{3}{5} \times 3 = \frac{9}{5} = 1\frac{4}{5}

Rafael swims \displaystyle 1\frac{4}{5} miles per hour.

(b) Hours per mile means hours divided by miles:

\frac{1}{3} \div \frac{3}{5} = \frac{1}{3} \times \frac{5}{3} = \frac{5}{9}

He takes \displaystyle \frac{5}{9} of an hour per mile, which is \displaystyle \frac{5}{9} \times 60 = 33\frac{1}{3} minutes.

Check. The two unit rates should be reciprocals, and \displaystyle \frac{9}{5} \times \frac{5}{9} = 1. Also, the answer to (a) should be more than \displaystyle \frac{3}{5}, since a whole hour is longer than the third of an hour he swam.

Example 2

Fractions built out of fractions

Simplify (a) \displaystyle \dfrac{\frac{4}{9}}{\frac{2}{3}} \qquad (b) \displaystyle \dfrac{6}{\frac{3}{5}} \qquad (c) \displaystyle \dfrac{\frac{7}{10}}{14} \qquad (d) \displaystyle \dfrac{\frac{5}{6}}{\frac{3}{4}}

Solution

The long bar means division, and dividing by a number is multiplying by its reciprocal.

(a) \displaystyle \dfrac{\frac{4}{9}}{\frac{2}{3}} = \frac{4}{9} \times \frac{3}{2} = \frac{12}{18} = \frac{2}{3}.

(b) A whole number is a fraction over 1, and only the bottom needs flipping: \displaystyle \dfrac{6}{\frac{3}{5}} = 6 \times \frac{5}{3} = \frac{30}{3} = 10. That is sensible: \displaystyle \frac{3}{5} fits into 6 ten times, since ten lots of \displaystyle \frac{3}{5} make \displaystyle \frac{30}{5} = 6.

(c) The reciprocal of 14 is \displaystyle \frac{1}{14}, so \displaystyle \dfrac{\frac{7}{10}}{14} = \frac{7}{10} \times \frac{1}{14} = \frac{7}{140} = \frac{1}{20}.

(d) This time use the second way. The smallest number that both 6 and 4 divide is 12, so multiply top and bottom by 12, which multiplies the fraction by \displaystyle \frac{12}{12} = 1:

\dfrac{\frac{5}{6}}{\frac{3}{4}} = \dfrac{\frac{5}{6} \times 12}{\frac{3}{4} \times 12} = \frac{10}{9}

Check (d) the first way: \displaystyle \frac{5}{6} \times \frac{4}{3} = \frac{20}{18} = \frac{10}{9}.

Example 3

When the time is not a unit fraction

Oskar walks \displaystyle \frac{3}{4} of a mile in 16 minutes at a steady pace. Find his speed in miles per hour.

Solution

The rate asked for is per hour, so first write the time in hours. An hour has 60 minutes, so 16 minutes is \displaystyle \frac{16}{60} = \frac{4}{15} of an hour.

Down to one part. \displaystyle \frac{4}{15} of an hour is four fifteenths, so one fifteenth of an hour carries a quarter of the distance:

\frac{3}{4} \div 4 = \frac{3}{16}

Up to a whole. An hour is fifteen fifteenths:

15 \times \frac{3}{16} = \frac{45}{16} = 2\frac{13}{16}

In one line, dividing by \displaystyle \frac{4}{15} is multiplying by its reciprocal: \displaystyle \frac{3}{4} \div \frac{4}{15} = \frac{3}{4} \times \frac{15}{4} = \frac{45}{16}. Oskar walks at \displaystyle 2\frac{13}{16} miles per hour.

Check. At \displaystyle \frac{45}{16} miles per hour, \displaystyle \frac{4}{15} of an hour covers \displaystyle \frac{45}{16} \times \frac{4}{15} = \frac{180}{240} = \frac{3}{4} of a mile. The size is sensible too: covering \displaystyle \frac{3}{4} of a mile in exactly a quarter of an hour would be 3 miles per hour, and Oskar took a little longer than that, so he is a little slower than 3.

Example 4

Mixed numbers on both sides

(a) Mateo walks \displaystyle 2\frac{1}{2} miles in \displaystyle \frac{3}{4} of an hour. Find his speed in miles per hour, and how many minutes he takes per mile.

(b) Dagny walks \displaystyle 4\frac{1}{5} miles in \displaystyle 1\frac{1}{2} hours. Find her speed in miles per hour.

Solution

(a) Write \displaystyle 2\frac{1}{2} as \displaystyle \frac{5}{2}, then divide miles by hours:

\frac{5}{2} \div \frac{3}{4} = \frac{5}{2} \times \frac{4}{3} = \frac{20}{6} = \frac{10}{3} = 3\frac{1}{3}

Mateo walks at \displaystyle 3\frac{1}{3} miles per hour. Hours per mile is the reciprocal, \displaystyle \frac{3}{10} of an hour, and \displaystyle \frac{3}{10} \times 60 = 18 minutes per mile.

(b) Both amounts are mixed numbers, so rewrite both: \displaystyle 4\frac{1}{5} = \frac{21}{5} and \displaystyle 1\frac{1}{2} = \frac{3}{2}.

\frac{21}{5} \div \frac{3}{2} = \frac{21}{5} \times \frac{2}{3} = \frac{42}{15} = \frac{14}{5} = 2\frac{4}{5}

Dagny walks at \displaystyle 2\frac{4}{5} miles per hour. This time the time is more than an hour, so the unit rate comes out smaller than the distance walked, as it should.

Example 5

A fraction of a fence

Wen paints \displaystyle \frac{3}{8} of a fence in \displaystyle \frac{3}{4} of an hour, at a steady pace. (a) What fraction of the fence does she paint per hour? (b) How long would the whole fence take? (c) How much longer does she need to finish it?

\displaystyle \frac{1}{4}\,\text{h}
\displaystyle \frac{1}{4}\,\text{h}
\displaystyle \frac{1}{4}\,\text{h}
1\ \text{hour}
2\ \text{hours}
Figure 3Three eighths of the fence took three quarter-hours, so each eighth takes a quarter of an hour.
Solution

The picture does it by counting. Three eighths of the fence took three quarter-hours, so each eighth takes a quarter of an hour. One hour is four quarter-hours, enough for four eighths, which is half the fence.

(a) The arithmetic says the same, with the whole fence as the unit:

\frac{3}{8} \div \frac{3}{4} = \frac{3}{8} \times \frac{4}{3} = \frac{12}{24} = \frac{1}{2}

Wen paints \displaystyle \frac{1}{2} of the fence per hour.

(b) Hours per fence is the reciprocal: \displaystyle \frac{3}{4} \div \frac{3}{8} = 2 hours. In the picture, all eight eighths at a quarter-hour each make 2 hours.

(c) What is left is \displaystyle 1 - \frac{3}{8} = \frac{5}{8} of the fence. At \displaystyle \frac{1}{2} of the fence per hour, the time is the amount divided by the rate:

\frac{5}{8} \div \frac{1}{2} = \frac{5}{8} \times 2 = \frac{5}{4} = 1\frac{1}{4}

She needs another \displaystyle 1\frac{1}{4} hours. Check: \displaystyle \frac{3}{4} + \frac{5}{4} = 2 hours in all, which agrees with (b).

Example 6

Which of two mowers is faster

Lucía mows \displaystyle \frac{3}{10} of an acre in \displaystyle \frac{2}{5} of an hour. Tomás mows \displaystyle \frac{2}{3} of an acre in \displaystyle \frac{5}{6} of an hour. Both work at a steady pace. Who mows faster?

Solution

Tomás mowed more grass, but he also took longer, so the raw numbers cannot decide. Find each unit rate in acres per hour:

\begin{aligned} \text{Lucía:}\quad \frac{3}{10} \div \frac{2}{5} &= \frac{3}{10} \times \frac{5}{2} = \frac{15}{20} = \frac{3}{4} \\ \text{Tomás:}\quad \frac{2}{3} \div \frac{5}{6} &= \frac{2}{3} \times \frac{6}{5} = \frac{12}{15} = \frac{4}{5} \end{aligned}

To compare \displaystyle \frac{3}{4} and \displaystyle \frac{4}{5}, write both over 20: \displaystyle \frac{15}{20} and \displaystyle \frac{16}{20}. Tomás mows \displaystyle \frac{4}{5} of an acre per hour and Lucía \displaystyle \frac{3}{4}, so Tomás is faster, though only by \displaystyle \frac{1}{20} of an acre each hour.

Check with the other unit rate. Hours per acre: Lucía \displaystyle \frac{2}{5} \div \frac{3}{10} = \frac{4}{3}, Tomás \displaystyle \frac{5}{6} \div \frac{2}{3} = \frac{5}{4}. Over 12 these are \displaystyle \frac{16}{12} and \displaystyle \frac{15}{12}, so Tomás needs less time per acre. Both comparisons agree, as they must.

Example 7

Honey per batch of granola

Zeynep makes \displaystyle \frac{3}{4} of a batch of granola and uses \displaystyle \frac{1}{2} cup of honey. (a) How much honey does one batch use? (b) How many batches does one cup of honey make? (c) She has \displaystyle 1\frac{1}{4} cups of honey left. How many batches can it make?

Solution

(a) Cups per batch is cups divided by batches:

\frac{1}{2} \div \frac{3}{4} = \frac{1}{2} \times \frac{4}{3} = \frac{4}{6} = \frac{2}{3}

One batch uses \displaystyle \frac{2}{3} cup of honey. It is more than \displaystyle \frac{1}{2} cup, as it should be, since a whole batch is bigger than the three-quarter batch she made.

(b) Batches per cup is the reciprocal, \displaystyle \frac{3}{4} \div \frac{1}{2} = \frac{3}{2} = 1\frac{1}{2} batches.

(c) Each cup makes \displaystyle \frac{3}{2} batches, so \displaystyle \frac{5}{4} cups make

\frac{5}{4} \times \frac{3}{2} = \frac{15}{8} = 1\frac{7}{8}

batches. The same answer comes from asking how many lots of \displaystyle \frac{2}{3} cup fit into \displaystyle \frac{5}{4} cups: \displaystyle \frac{5}{4} \div \frac{2}{3} = \frac{5}{4} \times \frac{3}{2} = \frac{15}{8}.

Example 8

Why keep the fractions exact

A swimmer covers \displaystyle \frac{1}{3} of a mile in 10 minutes. (a) Find the speed in miles per hour, exactly. (b) Someone rounds the amounts to 0.33 mile and 0.17 hour first. What speed do they get? (c) Use each speed to predict how far the swimmer goes in \displaystyle 1\frac{1}{2} hours at the same pace.

Solution

(a) 10 minutes is \displaystyle \frac{10}{60} = \frac{1}{6} of an hour, and six sixths make an hour:

\frac{1}{3} \div \frac{1}{6} = \frac{1}{3} \times 6 = 2

The speed is exactly 2 miles per hour.

(b) 0.33 \div 0.17 \approx 1.94 miles per hour, to two decimal places. Both roundings were small, but they pulled in opposite directions: 0.33 is a little less than \displaystyle \frac{1}{3} and 0.17 is a little more than \displaystyle \frac{1}{6}, so the quotient comes out too small on both counts.

(c) Exactly, \displaystyle 2 \times \frac{3}{2} = 3 miles. With the rounded rate, 1.94 \times 1.5 = 2.91 miles, almost a tenth of a mile short. The fractions gave a simple, exact answer; the decimals gave a worse one with more work.

Boundaries

The second amount cannot be zero. A rate per one hour needs some time to have passed. Dividing by 0 has no value, so a complex fraction with 0 as its whole bottom is not a number. The first amount may be 0: no distance in \displaystyle \frac{1}{4} of an hour is 0 miles per hour.

The pace has to be steady. Every step above assumed each quarter-hour, or each fifth of an hour, carries the same distance. If the pace changes, the same division gives the average rate over the stretch that was measured, and using it to predict another amount assumes that average holds.

The order of division decides which unit rate you get. Miles divided by hours is miles per hour; hours divided by miles is hours per mile. When neither amount is 0, the two are reciprocals, and they are equal only when both are 1. When the first amount is 0, only one of them exists: 0 miles per hour, but no hours per mile.

Units travel with the numbers. Miles divided by hours is in miles per hour, and fraction of a fence divided by hours is in fences per hour. Two amounts in the same unit, such as cups of oats divided by cups of honey, give a plain number: how many times as much of one there is.

A mixed number is one number. \displaystyle 2\frac{1}{2} is \displaystyle 2 + \frac{1}{2}, not \displaystyle 2 \times \frac{1}{2}, and it has to be rewritten as \displaystyle \frac{5}{2} before dividing.

Where this goes next

The unit rate is the number that turns one quantity into the other. When two quantities keep the same rate all the way along, as the miles and hours of a steady swim do, that number is the constant of proportionality, and the pair is one of the proportional relationships: every row of Hana’s table has \displaystyle \text{miles} = \frac{3}{2} \times \text{hours}. The fractions met here are what make those constants come out as fractions rather than whole numbers.

Speed is the most familiar rate of all, and converting a rate to other units, from miles per hour to feet per minute, multiplies by fractions of exactly the kind used here. Comparing two rates by putting them on the same “per” is also how unit prices decide which package is the better buy.

Complex fractions come back in algebra with letters in them, in the lesson on adding and subtracting rational expressions, which also covers complex fractions. A fraction whose top and bottom are themselves such expressions is simplified by the same two moves: divide, or multiply top and bottom by one expression that clears every small denominator. And division by a fraction extends to negative fractions in multiplying and dividing rational numbers, with the sign worked out separately.

Exercises

Part 1: fractions built out of fractions

Simplify.

  1. \displaystyle \dfrac{\frac{5}{6}}{\frac{1}{3}}
  2. \displaystyle \dfrac{\frac{3}{8}}{\frac{9}{10}}
  3. \displaystyle \dfrac{4}{\frac{2}{7}}
  4. \displaystyle \dfrac{\frac{9}{16}}{3}
  5. \displaystyle \dfrac{\frac{7}{12}}{\frac{7}{8}}, by multiplying top and bottom by 24.

Part 1: walking and swimming

Each person moves at a steady pace.

  1. A walker covers \displaystyle \frac{3}{4} of a mile in \displaystyle \frac{1}{5} of an hour. Find the speed in miles per hour.
  2. A swimmer covers \displaystyle \frac{2}{5} of a mile in \displaystyle \frac{1}{4} of an hour. Find the miles per hour and the hours per mile.
  3. A walker covers \displaystyle \frac{7}{10} of a mile in 10 minutes. Find the speed in miles per hour.
  4. A swimmer covers \displaystyle \frac{3}{8} of a mile in \displaystyle \frac{3}{10} of an hour. Find the speed in miles per hour, and how many minutes one mile takes.
  5. A walker covers \displaystyle \frac{4}{5} of a mile in \displaystyle \frac{4}{15} of an hour. Find the speed in miles per hour, and how far the walker goes in \displaystyle \frac{1}{2} of an hour.

Part 2: mixed numbers

  1. A walker covers \displaystyle 3\frac{1}{3} miles in \displaystyle 1\frac{1}{6} hours. Find the speed in miles per hour.
  2. A swimmer covers \displaystyle 1\frac{1}{8} miles in \displaystyle \frac{5}{6} of an hour. Find the speed in miles per hour.

Part 2: painting and mowing

Each person works at a steady pace.

  1. Ade paints \displaystyle \frac{2}{5} of a wall in \displaystyle \frac{1}{3} of an hour. How many walls does he paint per hour, and how many minutes does one whole wall take?
  2. Ruth mows \displaystyle \frac{5}{8} of a lawn in \displaystyle \frac{5}{6} of an hour. What fraction of the lawn does she mow per hour, and how long does the whole lawn take?
  3. A fence has 30 square meters to paint. Ilse paints \displaystyle 13\frac{1}{2} square meters of it in \displaystyle \frac{3}{4} of an hour. Find her rate in square meters per hour, and how many minutes the rest of the fence takes.
  4. Bram mows \displaystyle \frac{2}{3} of a field in \displaystyle 1\frac{1}{4} hours. What fraction of the field does he mow per hour, and how long does the rest take?

Part 2: per batch

  1. A third of a batch of pancakes uses \displaystyle \frac{1}{2} cup of milk. How much milk does one batch use, and how many batches does one cup of milk make?
  2. Two thirds of a batch of muffins uses \displaystyle 1\frac{1}{4} cups of flour. How much flour does one batch use, and how many batches can be made with 5 cups of flour?

Part 2: comparing rates

  1. Yusuf swims \displaystyle \frac{5}{8} of a mile in \displaystyle \frac{1}{3} of an hour. Mirela swims \displaystyle \frac{3}{4} of a mile in \displaystyle \frac{2}{5} of an hour. Who swims faster?
  2. Sven paints \displaystyle \frac{3}{10} of a room in \displaystyle \frac{1}{2} of an hour. Kemi paints \displaystyle \frac{1}{4} of a room of the same size in \displaystyle \frac{2}{5} of an hour. Who paints faster, and by how much of a room per hour?

Reasoning

  1. A walker covers some distance in \displaystyle \frac{3}{4} of an hour. Explain, without the rule for dividing fractions, why the distance per hour is the distance multiplied by \displaystyle \frac{4}{3}.
  2. A walk takes less than one hour. Explain why the number of miles per hour is greater than the number of miles walked. What happens if the walk takes more than one hour?
  3. Explain why, for any pair of amounts, the miles per hour and the hours per mile multiply to 1.
  4. Someone rounds \displaystyle \frac{2}{3} of a mile to 0.67 and 10 minutes to 0.17 hour, and finds a speed of about 3.94 miles per hour. Find the exact speed, and explain the difference.
  5. Explain why multiplying the top and the bottom of a complex fraction by the same non-zero number does not change its value, both as arithmetic and in terms of a rate.
Answers
  1. \displaystyle \frac{5}{2} = 2\frac{1}{2}. \displaystyle \frac{5}{6} \times 3 = \frac{15}{6} = \frac{5}{2}.
  2. \displaystyle \frac{5}{12}. \displaystyle \frac{3}{8} \times \frac{10}{9} = \frac{30}{72} = \frac{5}{12}.
  3. 14. \displaystyle 4 \times \frac{7}{2} = \frac{28}{2} = 14.
  4. \displaystyle \frac{3}{16}. \displaystyle \frac{9}{16} \times \frac{1}{3} = \frac{9}{48} = \frac{3}{16}.
  5. \displaystyle \frac{2}{3}. \displaystyle \frac{7}{12} \times 24 = 14 and \displaystyle \frac{7}{8} \times 24 = 21, so the fraction is \displaystyle \frac{14}{21} = \frac{2}{3}.
  6. \displaystyle 3\frac{3}{4} miles per hour. \displaystyle \frac{3}{4} \div \frac{1}{5} = \frac{3}{4} \times 5 = \frac{15}{4}.
  7. \displaystyle 1\frac{3}{5} miles per hour and \displaystyle \frac{5}{8} hour per mile. \displaystyle \frac{2}{5} \times 4 = \frac{8}{5}, and \displaystyle \frac{1}{4} \div \frac{2}{5} = \frac{1}{4} \times \frac{5}{2} = \frac{5}{8}.
  8. \displaystyle 4\frac{1}{5} miles per hour. 10 minutes is \displaystyle \frac{1}{6} of an hour, and \displaystyle \frac{7}{10} \times 6 = \frac{42}{10} = \frac{21}{5}.
  9. \displaystyle 1\frac{1}{4} miles per hour, and 48 minutes per mile. \displaystyle \frac{3}{8} \times \frac{10}{3} = \frac{10}{8} = \frac{5}{4}; hours per mile is \displaystyle \frac{4}{5}, and \displaystyle \frac{4}{5} \times 60 = 48.
  10. 3 miles per hour, and \displaystyle 1\frac{1}{2} miles in half an hour. \displaystyle \frac{4}{5} \times \frac{15}{4} = 3, and \displaystyle 3 \times \frac{1}{2} = \frac{3}{2}.
  11. \displaystyle 2\frac{6}{7} miles per hour. \displaystyle \frac{10}{3} \div \frac{7}{6} = \frac{10}{3} \times \frac{6}{7} = \frac{60}{21} = \frac{20}{7}.
  12. \displaystyle 1\frac{7}{20} miles per hour. \displaystyle \frac{9}{8} \times \frac{6}{5} = \frac{54}{40} = \frac{27}{20}.
  13. \displaystyle 1\frac{1}{5} walls per hour, and 50 minutes per wall. \displaystyle \frac{2}{5} \times 3 = \frac{6}{5}; hours per wall is \displaystyle \frac{5}{6}, and \displaystyle \frac{5}{6} \times 60 = 50.
  14. \displaystyle \frac{3}{4} of the lawn per hour, and \displaystyle 1\frac{1}{3} hours, that is 1 hour 20 minutes, for the whole lawn. \displaystyle \frac{5}{8} \times \frac{6}{5} = \frac{6}{8} = \frac{3}{4}, and the reciprocal is \displaystyle \frac{4}{3}.
  15. 18 square meters per hour, and 55 minutes for the rest. \displaystyle \frac{27}{2} \times \frac{4}{3} = 18. The rest is \displaystyle 30 - 13\frac{1}{2} = 16\frac{1}{2} square meters, and \displaystyle \frac{33}{2} \div 18 = \frac{33}{36} = \frac{11}{12} of an hour, which is 55 minutes.
  16. \displaystyle \frac{8}{15} of the field per hour, and \displaystyle \frac{5}{8} of an hour for the rest. \displaystyle \frac{2}{3} \div \frac{5}{4} = \frac{2}{3} \times \frac{4}{5} = \frac{8}{15}. The rest is \displaystyle \frac{1}{3} of the field, and \displaystyle \frac{1}{3} \div \frac{8}{15} = \frac{15}{24} = \frac{5}{8}. It is half of what was done, so it takes half the time.
  17. \displaystyle 1\frac{1}{2} cups per batch, and \displaystyle \frac{2}{3} of a batch per cup. \displaystyle \frac{1}{2} \div \frac{1}{3} = \frac{3}{2}, and the reciprocal is \displaystyle \frac{2}{3}.
  18. \displaystyle 1\frac{7}{8} cups per batch, and \displaystyle 2\frac{2}{3} batches from 5 cups. \displaystyle \frac{5}{4} \div \frac{2}{3} = \frac{5}{4} \times \frac{3}{2} = \frac{15}{8}; then \displaystyle 5 \div \frac{15}{8} = 5 \times \frac{8}{15} = \frac{8}{3}.
  19. Neither: both swim at \displaystyle 1\frac{7}{8} miles per hour. Yusuf, \displaystyle \frac{5}{8} \times 3 = \frac{15}{8}; Mirela, \displaystyle \frac{3}{4} \times \frac{5}{2} = \frac{15}{8}.
  20. Kemi, by \displaystyle \frac{1}{40} of a room per hour. Sven, \displaystyle \frac{3}{10} \times 2 = \frac{3}{5}; Kemi, \displaystyle \frac{1}{4} \times \frac{5}{2} = \frac{5}{8}. Over 40 these are \displaystyle \frac{24}{40} and \displaystyle \frac{25}{40}.
  21. \displaystyle \frac{3}{4} of an hour is three quarter-hours, and at a steady pace each carries the same distance, so one quarter-hour carries the distance divided by 3. An hour is four quarter-hours, so it carries four times that. Dividing by 3 and then multiplying by 4 is multiplying by \displaystyle \frac{4}{3}.
  22. The miles per hour is the miles divided by the hours. Dividing a positive number by a number between 0 and 1 gives a larger number, since it is the same as multiplying by the reciprocal, which is greater than 1. In terms of the walk: a whole hour is longer than the walk took, so at the same pace it covers more distance. If the walk takes more than one hour, an hour is only part of it, so the miles per hour is smaller than the miles walked; for exactly one hour the two are equal.
  23. If the walk is m miles in h hours, with both non-zero, the two unit rates are \displaystyle \frac{m}{h} and \displaystyle \frac{h}{m}, and \displaystyle \frac{m}{h} \times \frac{h}{m} = \frac{mh}{hm} = 1. Each is the same division done the other way round, so they are reciprocals.
  24. Exactly 4 miles per hour, since 10 minutes is \displaystyle \frac{1}{6} of an hour and \displaystyle \frac{2}{3} \times 6 = 4. The rounded quotient 0.67 \div 0.17 \approx 3.94 is off because 0.17 is larger than \displaystyle \frac{1}{6}, which pulls the result down more than the small rise from \displaystyle \frac{2}{3} to 0.67 pushes it up.
  25. As arithmetic: multiplying top and bottom by k multiplies the fraction by \displaystyle \frac{k}{k}, which is 1, and multiplying by 1 leaves any number unchanged. As a rate: it scales both amounts by the same factor, k times the distance in k times the time, which is the same pace, so the amount per one hour is unchanged. The number must be non-zero, or the bottom would become 0.
kg1128 · updated 2026-10-07 · CC-BY-SA-4.0