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What's on the worksheet
- Find dydx as a function of t and simplify.x = \sin 2t, y = \cos^2 tx = \ln(t^2 + 1), y = \arctan tx = te^t, y = e^{2t}
- Find the tangent line to the curve x = t² + 4t, y = t³ - 4t² at the point (5, −3).
- A point moves along x = e^t², y = t for -1 ≤ t ≤ 1.
- For the curve x = t³ - 3, y = -3t² - 2t, find dydx and d²ydx² at t = -2.
- Consider the curve x = t³ - 3t, y = t².
- Leah flies a survey drone in a loop over a field.
- Samir skates a trick line in a flat skate park plaza, filmed by a camera on a tall pole.
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The free lesson teaches it with worked examples and practice problems.
Derivatives of parametric curves: the lesson ›More Chapter 7 worksheets: Parametric, polar and vector-valued functions
- 7.1Derivatives of parametric curves
- 7.2Arc length and speed on parametric and polar curves
- 7.3Vector valued functions and motion in the plane
- 7.4Slope of a polar curve
- 7.5Area in polar coordinates