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- 39° A B M P ℓ In the figure, line is the perpendicular bisector of AB, and P is on .
- 32° 57° A B C D N In the figure, the perpendicular bisector of BC meets side AB at D.
- Let A = (-1, 4) and B = (5, 0), and let P = (x, y) be any point with PA = PB.
- Points A and B are 10 units apart, and M is the midpoint of AB.
- AB has midpoint M, and P is a point that is not on line AB.
- In PQR, PQ = PR and m P = 36^.
- Line is the perpendicular bisector of AB and crosses it at M.
- In ABC, the perpendicular bisector of BC passes through A and crosses BC at M.
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Perpendicular bisectors of a triangle: the lesson ›More Chapter 5 worksheets: Triangle segments, centers and inequalities
- 5.1Perpendicular bisectors of a triangle
- 5.2Circumcenter
- 5.3Angle bisectors of a triangle
- 5.4Incenter
- 5.5Medians and altitudes
- 5.6Centroid
- 5.7Orthocenter and the Euler line
- 5.8Sides and angles in order
- 5.9Proof by contradiction
- 5.10Indirect proof
- 5.11Hinge theorem