Grade 4 · 4.NF.C.5

Adding tenths and hundredths as fractions

In March the rain gauge in the rainforest filled to 3 tenths of a meter, and in April to 45 hundredths of a meter. How do you add a number of tenths to a number of hundredths, when the pieces are not the same size?

Where you are 5 in Adding and subtracting fractions

When you reach for it

Leyla and Tendai help at a research station in a rainforest. Each month they read a rain gauge, a tall tube marked in meters, and write down how deep the water stood. Some months they write the depth in tenths of a meter, such as \displaystyle \frac{3}{10} meter. Other months they read it more finely, in hundredths of a meter, such as \displaystyle \frac{45}{100} meter. At the end of April they want the total for March and April together.

The trouble is that the two amounts count pieces of different sizes. A tenth is a whole cut into 10 parts; a hundredth is a whole cut into 100 parts, so it is much smaller. Three of one and forty-five of the other are not 48 of anything. You can only add counts when they count the same piece: that is adding fractions with like denominators, where \displaystyle \frac{30}{100} + \frac{45}{100} is just 30 + 45 hundredths.

So you reach for this skill whenever an amount in tenths meets an amount in hundredths and the two must be put together: rainfall, lengths of rope or vine, and money, where a dime is a tenth of a dollar and a penny is a hundredth. It rests on tenths and hundredths, which showed that \displaystyle \frac{7}{10} = \frac{70}{100}, and on equivalent fractions in pictures: cutting every piece of a shaded shape into smaller equal pieces changes the numbers but not the amount.

The procedure

The lesson is taught in two parts, one a day.

Part 1: write the tenths as hundredths, then add

Take a square as one whole. Cut it into 10 columns: each column is one tenth. Now cut every column into 10 small squares. The whole is a 10 by 10 grid of 100 small squares, and each small square is one hundredth (a picture of a fraction as part of a shape is the area model).

Every column holds 10 small squares, so every tenth is 10 hundredths. Three tenths are three columns, which is 3 \times 10 = 30 small squares:

\frac{3}{10} = \frac{3 \times 10}{10 \times 10} = \frac{30}{100}

Multiplying the top and the bottom by 10 is the same as cutting each piece into 10. The bottom says the pieces are 10 times as many; the top says the count of shaded pieces is 10 times as large. The shaded amount does not change.

Now both amounts count hundredths, and counts of the same piece add like whole numbers:

\frac{3}{10} + \frac{45}{100} = \frac{30}{100} + \frac{45}{100} = \frac{75}{100}
+ = 3 tenths = 30 hundredths 45 hundredths 75 hundredths = 0.75
Figure 1\displaystyle \frac{3}{10} + \frac{45}{100} on hundred grids. The three shaded columns are also 30 small squares, so the sum is 30 + 45 = 75 small squares, \displaystyle \frac{75}{100} = 0.75.

The bottom number stays 100. Adding 30 small squares to 45 small squares gives 75 small squares, and they are still hundredths. Adding the bottoms as well would say the squares had changed size, and they have not.

The answer can be written as a decimal too. Seventy-five hundredths is 7 full columns and 5 more squares, so it is 7 tenths and 5 hundredths:

\frac{75}{100} = 0.75

Three things make this work every time.

  • A tenth always splits into hundredths exactly. Since 10 \times 10 = 100, any number of tenths is ten times as many hundredths. Going the other way does not always work: 45 hundredths is 4 columns and 5 loose squares, not a whole number of tenths. That is why the tenths are rewritten, not the hundredths.
  • Order does not matter. \displaystyle \frac{45}{100} + \frac{3}{10} gives the same \displaystyle \frac{75}{100}, because of the commutative property of addition. With three amounts you may also add any two first (the associative property), for example the two tenths before the hundredths.
  • A decimal is already a count of tenths or hundredths. 0.6 is \displaystyle \frac{6}{10} and 0.27 is \displaystyle \frac{27}{100}. To add amounts given as decimals, write each as a fraction and add as above.

Part 2: sums past one whole, and word problems

A grid holds 100 small squares, so 100 hundredths make one whole:

\frac{100}{100} = 1

When a sum of hundredths reaches 100 or more, the extra squares spill onto a second grid. In October and November the rainforest gauge read \displaystyle \frac{8}{10} meter and \displaystyle \frac{56}{100} meter. The total is

\frac{8}{10} + \frac{56}{100} = \frac{80}{100} + \frac{56}{100} = \frac{136}{100}
+ 1 whole 100 hundredths 36 hundredths 136 hundredths = 1.36
Figure 2\displaystyle \frac{80}{100} + \frac{56}{100} = \frac{136}{100}. One hundred of the squares fill a whole grid, and the other 36 spill onto a second grid: \displaystyle 1\frac{36}{100} = 1.36.

Split the 136 squares into one full grid and the rest:

\frac{136}{100} = \frac{100}{100} + \frac{36}{100} = 1\frac{36}{100} = 1.36

The same total has three names. As a fraction it is \displaystyle \frac{136}{100}. As a mixed number, a whole number and a fraction together (see Mixed numbers and improper fractions), it is \displaystyle 1\frac{36}{100}. As a decimal it is 1.36, read “one and thirty-six hundredths”.

When the amounts already have whole parts, add the wholes and add the parts. The parts may pass one whole again, and then that whole joins the others. Every amount in a sum must be of the same whole: meters with meters, dollars with dollars.

Worked examples

Examples 1 to 4 go with Part 1, and Examples 5 to 7 with Part 2.

Example 1

March and April

In March the gauge read \displaystyle \frac{3}{10} meter and in April \displaystyle \frac{45}{100} meter. How much rain fell in the two months together? Give the answer as a fraction and as a decimal.

Solution

The amounts count different pieces, so first write the tenths as hundredths. Each tenth is 10 hundredths, so \displaystyle \frac{3}{10} = \frac{30}{100}. Now both count hundredths:

\frac{30}{100} + \frac{45}{100} = \frac{30 + 45}{100} = \frac{75}{100}

The bottom stays 100 because the pieces are still hundredths. In the first figure, 75 squares are 7 full columns and 5 more, so \displaystyle \frac{75}{100} = 0.75. In the two months 0.75 meter of rain fell.

Check: a hundredth of a meter is one centimeter, so the months gave 30 cm and 45 cm, and 30 + 45 = 75 cm, which is 0.75 meter.

Example 2

Amounts given as decimals

Tendai’s notebook says 0.6 meter of rain in June and 0.27 meter in July. Write each as a fraction and find the total.

Solution

The 6 in 0.6 is in the tenths place, so \displaystyle 0.6 = \frac{6}{10}. The two digits of 0.27 end in the hundredths place, so \displaystyle 0.27 = \frac{27}{100}. Write the tenths as hundredths and add:

\frac{6}{10} + \frac{27}{100} = \frac{60}{100} + \frac{27}{100} = \frac{87}{100}

The total is \displaystyle \frac{87}{100} = 0.87 meter. It holds 8 tenths and 7 hundredths: the 6 tenths from June, plus the 2 tenths and 7 hundredths from July.

Example 3

Three months

Deniz adds three readings: \displaystyle \frac{2}{10} meter, \displaystyle \frac{16}{100} meter and \displaystyle \frac{5}{10} meter. Find the total, and show that adding the two tenths first gives the same answer.

Solution

Write every tenth as hundredths: \displaystyle \frac{2}{10} = \frac{20}{100} and \displaystyle \frac{5}{10} = \frac{50}{100}. Then

\frac{20}{100} + \frac{16}{100} + \frac{50}{100} = \frac{86}{100} = 0.86

Another way: the commutative property lets the two tenths sit side by side, and the associative property lets them be added first. Two tenths and five tenths are the same piece already, so \displaystyle \frac{2}{10} + \frac{5}{10} = \frac{7}{10}. Then

\frac{7}{10} + \frac{16}{100} = \frac{70}{100} + \frac{16}{100} = \frac{86}{100}

Both ways give 0.86 meter, as they must.

Example 4

The rest of the month

By July 20 the gauge had collected \displaystyle \frac{4}{10} meter of rain. The total for all of July was \displaystyle \frac{93}{100} meter. How much rain fell after July 20?

Solution

The unknown amount is the number that adds to \displaystyle \frac{4}{10} to make \displaystyle \frac{93}{100}. Write the tenths as hundredths so both amounts count the same piece: \displaystyle \frac{4}{10} = \frac{40}{100}. The question is now

\frac{40}{100} + \frac{?}{100} = \frac{93}{100}

Forty squares and how many more make 93 squares? Since 40 + 53 = 93, the answer is \displaystyle \frac{53}{100} meter, or 0.53 meter. Check: \displaystyle \frac{40}{100} + \frac{53}{100} = \frac{93}{100}.

Example 5

Past one whole

The gauge read \displaystyle \frac{8}{10} meter in October and \displaystyle \frac{56}{100} meter in November. Find the total as a fraction, a mixed number and a decimal.

Solution

Write the tenths as hundredths and add:

\frac{8}{10} + \frac{56}{100} = \frac{80}{100} + \frac{56}{100} = \frac{136}{100}

The top is bigger than the bottom, so the total is more than one whole meter. A hundred of the 136 hundredths make one whole, as the second figure shows, and 36 are left:

\frac{136}{100} = 1 + \frac{36}{100} = 1\frac{36}{100} = 1.36

The two months gave 1.36 meters of rain. That fits a quick look at the parts: \displaystyle \frac{8}{10} is close to one whole and \displaystyle \frac{56}{100} is more than half, so the total had to be more than one meter.

Example 6

Two rainy seasons

Leyla’s records show \displaystyle 2\frac{7}{10} meters of rain in the first rainy season and \displaystyle 1\frac{52}{100} meters in the second. How much rain fell in both seasons?

Solution

A mixed number is a whole number plus a fraction, so \displaystyle 2\frac{7}{10} = 2 + \frac{7}{10} and \displaystyle 1\frac{52}{100} = 1 + \frac{52}{100}. The order and grouping of a sum do not change it, so add the wholes together and the parts together:

2 + 1 = 3, \qquad \frac{7}{10} + \frac{52}{100} = \frac{70}{100} + \frac{52}{100} = \frac{122}{100}

The parts passed one whole: \displaystyle \frac{122}{100} = 1\frac{22}{100}. That extra whole joins the other 3:

3 + 1\frac{22}{100} = 4\frac{22}{100} = 4.22

Both seasons together gave 4.22 meters of rain.

Example 7

Dimes and pennies

Deniz wants a waterproof notebook for the station that costs 1.50 dollars. She has 7 dimes and 85 pennies. How much money does she have, and is it enough?

Solution

A dime is 10 cents, one tenth of a dollar, so 7 dimes are \displaystyle \frac{7}{10} dollar. A penny is one hundredth of a dollar, so 85 pennies are \displaystyle \frac{85}{100} dollar. Add:

\frac{7}{10} + \frac{85}{100} = \frac{70}{100} + \frac{85}{100} = \frac{155}{100} = 1\frac{55}{100}

She has 1.55 dollars. The notebook costs 1.50 dollars, which is \displaystyle \frac{150}{100} dollar. She has 155 hundredths of a dollar and needs 150, so she has enough, with 5 cents left over.

Boundaries

  • The pieces must be the same size before they are added. Tenths are rewritten as hundredths, and only then are the tops added. The bottom of the answer is 100, not 10 + 100.
  • Tenths go to hundredths, not always back. Every number of tenths is a whole number of hundredths, because 10 \times 10 = 100. A number of hundredths is a whole number of tenths only when it ends in 0: \displaystyle \frac{40}{100} = \frac{4}{10}, but \displaystyle \frac{45}{100} is not any whole number of tenths.
  • Tenths and hundredths only. This move works because 10 goes into 100 exactly. Adding, say, thirds and fourths needs a different shared piece; that is adding fractions with unlike denominators.
  • The same whole. \displaystyle \frac{3}{10} of a meter and \displaystyle \frac{45}{100} of a dollar cannot be added: the fractions are parts of different wholes, so their sum names nothing.
  • More than one whole. When the top reaches 100 hundredths or more, the sum is at least one whole and is often easier to read as a mixed number or a decimal with a whole part, such as \displaystyle 1\frac{36}{100} = 1.36.

Where this goes next

Adding by renaming pieces is the start of all fraction addition with different bottoms: the parent idea is adding fractions after renaming them in the same pieces, and the general case is adding fractions with unlike denominators.

For decimals, the same idea becomes a column method. Lining up the decimal points puts tenths under tenths and hundredths under hundredths, so the pieces match without writing any fractions; that is adding and subtracting decimals. Seeing where a sum such as 1.36 sits between 1 and 2 is decimals on a number line, and deciding whether 1.55 dollars is more than 1.50 dollars is comparing decimals. Sums of prices are worked further in money written as decimals.

Exercises

Exercises 1 to 12 go with Part 1, and 13 to 22 with Part 2. The reasoning group draws on both.

Part 1: write the tenths as hundredths, then add

  1. Write as hundredths: (a) \displaystyle \frac{4}{10}, (b) \displaystyle \frac{9}{10}.
  2. Add: \displaystyle \frac{2}{10} + \frac{35}{100}. Give the answer as a fraction and a decimal.
  3. Add: \displaystyle \frac{5}{10} + \frac{41}{100}. Give the answer as a fraction and a decimal.
  4. Add: \displaystyle \frac{13}{100} + \frac{7}{10}.
  5. Add: \displaystyle \frac{1}{10} + \frac{9}{100}. Write the answer as a decimal.
  6. Write 0.4 and 0.29 as fractions, then add them.
  7. Leyla’s gauge read 0.5 meter in January and 0.08 meter in February. Find the total as a fraction and a decimal of a meter, and in centimeters.
  8. Add: \displaystyle \frac{3}{10} + \frac{12}{100} + \frac{4}{10}.
  9. Find the missing number: \displaystyle \frac{6}{10} + \frac{?}{100} = \frac{71}{100}.
  10. A vine near the station grows \displaystyle \frac{2}{10} meter one week and \displaystyle \frac{23}{100} meter the next. How much did it grow in the two weeks?
  11. Write 0.7 and 0.14 as fractions with bottom 100, then add them.
  12. Find the missing number of tenths: \displaystyle \frac{?}{10} + \frac{5}{100} = \frac{65}{100}.

Part 2: sums past one whole, and word problems

  1. Add: \displaystyle \frac{9}{10} + \frac{24}{100}. Write the answer as a fraction, a mixed number and a decimal.
  2. Add: \displaystyle \frac{7}{10} + \frac{63}{100}. Write the answer as a mixed number and a decimal.
  3. Add: \displaystyle 1\frac{3}{10} + 2\frac{41}{100}.
  4. Add: \displaystyle 4\frac{6}{10} + \frac{75}{100}. Write the answer as a mixed number and a decimal.
  5. Add: \displaystyle \frac{5}{10} + \frac{5}{100} + \frac{5}{10}. Write the answer as a decimal.
  6. Tendai has 6 dimes and 72 pennies. How many dollars is that?
  7. Deniz has 0.8 dollar in one pocket and 0.65 dollar in another. A map of the trails costs 1.50 dollars. Does she have enough?
  8. The two wettest months gave \displaystyle \frac{9}{10} meter and \displaystyle \frac{79}{100} meter of rain. Find the total as a mixed number and a decimal.
  9. Leyla joins two ropes end to end, without overlap: one is \displaystyle 1\frac{4}{10} meters long and the other is \displaystyle \frac{85}{100} meter. How long is the joined rope?
  10. Over three months the gauge read \displaystyle \frac{6}{10} meter, \displaystyle \frac{47}{100} meter and \displaystyle \frac{5}{10} meter. Find the total.

Reasoning

  1. Tendai writes \displaystyle \frac{4}{10} + \frac{25}{100} = \frac{29}{110}. Without working the right answer first, explain why his answer cannot be right. Then find the right sum.
  2. To add \displaystyle \frac{3}{10} + \frac{45}{100}, Deniz wants to write the hundredths as tenths instead of the tenths as hundredths. Explain why that does not work here, and say when hundredths can be written as tenths.
  3. Without finding the exact sum, explain why \displaystyle \frac{7}{10} + \frac{46}{100} is more than one whole.
Answers
  1. (a) \displaystyle \frac{40}{100}. (b) \displaystyle \frac{90}{100}. Each tenth is 10 hundredths.
  2. \displaystyle \frac{55}{100} = 0.55, since \displaystyle \frac{20}{100} + \frac{35}{100} = \frac{55}{100}.
  3. \displaystyle \frac{91}{100} = 0.91, since \displaystyle \frac{50}{100} + \frac{41}{100} = \frac{91}{100}.
  4. \displaystyle \frac{83}{100}, since \displaystyle \frac{13}{100} + \frac{70}{100} = \frac{83}{100}. The order does not matter.
  5. 0.19, since \displaystyle \frac{10}{100} + \frac{9}{100} = \frac{19}{100}.
  6. \displaystyle 0.4 = \frac{4}{10} = \frac{40}{100} and \displaystyle 0.29 = \frac{29}{100}, so the sum is \displaystyle \frac{69}{100} = 0.69.
  7. \displaystyle \frac{50}{100} + \frac{8}{100} = \frac{58}{100}, which is 0.58 meter, or 58 cm.
  8. \displaystyle \frac{30}{100} + \frac{12}{100} + \frac{40}{100} = \frac{82}{100} = 0.82.
  9. 11. Since \displaystyle \frac{6}{10} = \frac{60}{100} and 60 + 11 = 71, the missing fraction is \displaystyle \frac{11}{100}.
  10. \displaystyle \frac{20}{100} + \frac{23}{100} = \frac{43}{100}, which is 0.43 meter.
  11. \displaystyle 0.7 = \frac{70}{100} and \displaystyle 0.14 = \frac{14}{100}, so the sum is \displaystyle \frac{84}{100} = 0.84.
  12. 6. The tenths must give 65 - 5 = 60 hundredths, and \displaystyle \frac{60}{100} = \frac{6}{10}.
  13. \displaystyle \frac{90}{100} + \frac{24}{100} = \frac{114}{100} = 1\frac{14}{100} = 1.14.
  14. \displaystyle \frac{70}{100} + \frac{63}{100} = \frac{133}{100}, so \displaystyle 1\frac{33}{100} = 1.33.
  15. \displaystyle 3\frac{71}{100} = 3.71. Wholes: 1 + 2 = 3. Parts: \displaystyle \frac{30}{100} + \frac{41}{100} = \frac{71}{100}.
  16. \displaystyle 5\frac{35}{100} = 5.35. Parts: \displaystyle \frac{60}{100} + \frac{75}{100} = \frac{135}{100}, which is \displaystyle 1\frac{35}{100}, and \displaystyle 4 + 1\frac{35}{100} = 5\frac{35}{100}.
  17. 1.05. \displaystyle \frac{50}{100} + \frac{5}{100} + \frac{50}{100} = \frac{105}{100} = 1\frac{5}{100}, with a 0 holding the tenths place.
  18. 1.32 dollars: \displaystyle \frac{60}{100} + \frac{72}{100} = \frac{132}{100} = 1\frac{32}{100}.
  19. No. \displaystyle \frac{80}{100} + \frac{65}{100} = \frac{145}{100}, which is 1.45 dollars. She needs 150 hundredths and has 145, so she is 5 cents short.
  20. \displaystyle \frac{90}{100} + \frac{79}{100} = \frac{169}{100}, so \displaystyle 1\frac{69}{100} = 1.69 meters.
  21. 2.25 meters. Parts: \displaystyle \frac{40}{100} + \frac{85}{100} = \frac{125}{100} = 1\frac{25}{100}, and \displaystyle 1 + 1\frac{25}{100} = 2\frac{25}{100}.
  22. \displaystyle \frac{60}{100} + \frac{47}{100} + \frac{50}{100} = \frac{157}{100} = 1\frac{57}{100}, which is 1.57 meters.
  23. Adding a positive amount to \displaystyle \frac{4}{10} must give more than \displaystyle \frac{4}{10}, which is \displaystyle \frac{40}{100}. But \displaystyle \frac{29}{110} is less than \displaystyle \frac{29}{100}, smaller even than \displaystyle \frac{4}{10} alone. He added tops and bottoms as if the pieces were the same size. Right sum: \displaystyle \frac{40}{100} + \frac{25}{100} = \frac{65}{100}.
  24. On a hundred grid, 45 squares are 4 full columns and 5 loose squares, so \displaystyle \frac{45}{100} is not a whole number of tenths. Every tenth, though, is exactly 10 hundredths. Hundredths can be written as tenths only when their count is a multiple of 10, such as \displaystyle \frac{40}{100} = \frac{4}{10}.
  25. \displaystyle \frac{7}{10} + \frac{3}{10} is one whole, and \displaystyle \frac{3}{10} is \displaystyle \frac{30}{100}. Since \displaystyle \frac{46}{100} is more than \displaystyle \frac{30}{100}, the sum is more than one whole. In hundredths, 70 + 46 is more than 100.
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