Adding and subtracting fractions with unlike denominators
Aiyana practices at the barre for one half of an hour, then works on jumps for three tenths of an hour. Halves and tenths are different sizes, so how do you add them?
Where you are 5 in Adding and subtracting fractions
When you reach for it
Aiyana, Dohyun and Lanre take a ballet class. They keep a log of their practice time, in fractions of an hour, and they learn their routine a piece at a time, so they talk about fractions of a routine too. After class they make paper banners for the spring show, and each banner gets painted in parts.
When two amounts are counted in the same pieces, adding them is easy. Two tenths and three tenths are five tenths, because tenths can be counted like apples (Adding and subtracting fractions with like denominators). But Aiyana’s log says \tfrac{1}{2} hour at the barre and \tfrac{3}{10} hour of jumps. Halves and tenths are different sizes. You reach for this lesson whenever two fractions with different denominators must be joined or one taken from the other. It has four parts, one for each day:
- Part 1: why different pieces cannot be counted together, and two pictures that fix it: fraction strips and area models.
- Part 2: adding when one denominator is a multiple of the other, and simplifying the answer.
- Part 3: adding when neither denominator is a multiple of the other, using the product of the denominators or the least common denominator.
- Part 4: subtracting, sums greater than 1, and adding three fractions.
The procedure
Part 1: the pieces must match
A fraction counts pieces. \tfrac{1}{2} is 1 piece of size one half. \tfrac{3}{10} is 3 pieces of size one tenth. Adding means putting the pieces together and saying how many there are. But 1 big piece and 3 small pieces are not “4” of anything. There is no single piece size to name.
Try adding the tops and the bottoms anyway, and you get \tfrac{4}{12}. That cannot be right. \tfrac{4}{12} is the same as \tfrac{1}{3}, which is less than \tfrac{1}{2}. Aiyana’s total practice cannot be less than her time at the barre alone. So the bottom numbers do not add. The denominator is not a count. It names the size of the pieces.
Fraction strips. The fix is to cut the pieces again until both fractions use one size. A half is the same as 5 tenths, because cutting a half into 5 equal parts makes pieces that are each one tenth of the whole strip.
Now both amounts are in tenths, so count them: 5 tenths and 3 tenths make 8 tenths.
Aiyana practiced \tfrac{8}{10} of an hour. Notice that only the halves were cut again. The tenths were already small enough.
Area models. Sometimes neither strip fits inside the other. Thirds cannot be cut into quarters, and quarters cannot be cut into thirds. A square solves this. Cut it into 3 rows to show thirds. Cut a square of the same size into 4 columns to show quarters. Then draw the other set of lines on each square too, as dashed lines.
Each square is now 3 rows by 4 columns, which is 3 \times 4 = 12 equal cells, so every cell is one twelfth. Two rows of the first square cover 2 \times 4 = 8 cells. One column of the second square covers 3 cells. So
The grid trick always works. Rows for one denominator and columns for the other cut the whole into pieces that both fractions can be counted in. Parts 2 and 3 do the same cutting with numbers instead of pictures.
Part 2: one denominator is a multiple of the other
Cutting each half into 5 parts is the same as multiplying the top and the bottom of \tfrac{1}{2} by 5. There are 5 times as many pieces, and each one is 5 times smaller, so the amount does not change (Equivalent fractions). Multiplying the top and bottom by 5 is the same as multiplying by \tfrac{5}{5}, which is 1.
How do you know to use 5? Because 10 is a multiple of 2: 2 \times 5 = 10. When the larger denominator is a multiple of the smaller one, the larger denominator is the shared piece size, and only one fraction has to change. To test it, divide the larger denominator by the smaller. If the answer is a whole number, that number is what the other fraction gets multiplied by.
With the pieces matched, add the numerators and keep the denominator. The denominator stays because the pieces are still tenths; you have only counted more of them. In general, for fractions with the same denominator d,
Simplifying the answer. The sum \tfrac{8}{10} is correct, but it can be written with fewer, bigger pieces. Both 8 and 10 can be divided by 2. Joining the tenths in pairs makes fifths, since 2 tenths is 1 fifth, and 8 tenths make 4 such pairs.
A fraction is in simplest form when no whole number bigger than 1 divides both its top and its bottom. Both \tfrac{8}{10} and \tfrac{4}{5} are right, and they name the same amount, but the simplest form is the one people usually write, because it is easiest to picture. So Aiyana’s practice was \tfrac{4}{5} of an hour, which is 48 minutes.
Part 3: neither denominator is a multiple of the other
For \tfrac{2}{3} + \tfrac{1}{4}, neither 3 nor 4 divides the other. Both fractions must change. The area model used 3 \times 4 = 12 cells, and the numbers do the same thing. Multiply the top and bottom of \tfrac{2}{3} by 4, which is cutting each third into 4 parts. Multiply the top and bottom of \tfrac{1}{4} by 3, which is cutting each quarter into 3 parts.
The product of the denominators always works as a common denominator. Each fraction is multiplied, top and bottom, by the other fraction’s denominator, and both bottoms become the same product. It needs no searching.
The least common denominator is the smallest number other than 0 that both denominators divide into evenly. Renaming two fractions this way has its own lesson, Common denominators and the least common denominator, and the search uses lists of multiples: list multiples of the larger denominator until one is also a multiple of the smaller. For 3 and 4 the list is 4, 8, 12, and 12 is the first that 3 divides. Here the least common denominator is the product. That happens whenever the two denominators share no factor except 1.
When the denominators do share a factor, the least common denominator is smaller than the product. For sixths and eighths, the product is 6 \times 8 = 48, but the multiples of 8 go 8, 16, 24, and 24 is already a multiple of 6. Either choice gives the same final answer, because forty-eighths are just twenty-fourths cut in half. The smaller choice keeps the numbers small and often means less simplifying at the end. The product is a safe fallback when the least common denominator does not come to mind.
Part 4: subtracting, sums greater than one, three fractions
Subtracting. Taking away has the same problem as adding: you cannot take 3 eighths from 5 sixths until both are counted in one size. The move is the same. For \tfrac{5}{6} - \tfrac{3}{8}, the least common denominator is 24, as Part 3 found. Cut each sixth into 4 and each eighth into 3:
Once the pieces match, subtract the numerators and keep the denominator, for the same reason as before: the pieces are still twenty-fourths.
On the number line, the difference is the distance from \tfrac{3}{8} up to \tfrac{5}{6}. In twenty-fourths that is 20 - 9 = 11 marks. In this lesson the first fraction is always the larger one, so the difference is never below zero. Subtracting a larger fraction from a smaller one gives a negative number, which Operations with rational numbers handles.
Sums greater than one. Two fractions less than 1 can add up to more than 1. Dohyun practices \tfrac{4}{5} hour on Monday and \tfrac{1}{2} hour on Tuesday:
The top is bigger than the bottom, so this is more than one whole hour. Ten of the thirteen tenths make 1 whole, and 3 tenths are left over, so \tfrac{13}{10} = 1\tfrac{3}{10}. The mixed number 1\tfrac{3}{10} reads “one and three tenths”: one whole hour and three tenths of another. To turn a fraction into a mixed number, divide the top by the bottom. The quotient is the whole number and the remainder is the new top: 13 \div 10 = 1 remainder 3. Simplify the fraction part if it can be simplified.
Three fractions. Adding three fractions works the same way. Find one denominator that all three denominators divide into, rename each fraction, and add the three numerators. Example 8 does this. Addition can be grouped and ordered in any way (the associative and commutative properties), so you may also add two first and then the third, but one shared denominator for all three is usually fewer steps.
Checking. Before trusting an answer, ask whether its size makes sense. \tfrac{4}{5} is close to 1 and \tfrac{1}{2} is a half, so their sum should be a bit less than 1\tfrac{1}{2}, and 1\tfrac{3}{10} is. Rounding each fraction to 0, \tfrac{1}{2} or 1 this way is the subject of Estimating with fractions.
Worked examples
Examples 1 and 2 belong to Part 1, Examples 3 and 4 to Part 2, Examples 5 and 6 to Part 3, and Examples 7 and 8 to Part 4.
A banner on fraction strips
Dohyun paints \tfrac{1}{4} of a paper banner red and \tfrac{3}{8} of it blue. What fraction of the banner is painted?
SolutionDraw the banner as a strip cut into quarters. Eighths are smaller than quarters, and each quarter can be cut into 2 eighths, so cut every quarter in half. Now the strip shows 8 eighths, and the red quarter covers 2 of them.
The blue part is 3 eighths, so the painted part is 2 + 3 = 5 eighths. Dohyun has painted \tfrac{5}{8} of the banner. This makes sense: \tfrac{1}{4} and \tfrac{3}{8} are each less than a half, and their sum is a little more than a half.
An area model for thirds and fifths
Lanre’s routine has three sections. The opening is \tfrac{1}{3} of the routine and the middle is \tfrac{2}{5} of it. What fraction of the routine are the opening and the middle together?
SolutionThirds do not fit into fifths, and fifths do not fit into thirds, so use an area model. Draw a square cut into 3 rows for thirds and 5 columns for fifths. That makes 3 \times 5 = 15 equal cells, so each cell is \tfrac{1}{15} of the square.
One row is \tfrac{1}{3}, and a row holds 5 cells, so \tfrac{1}{3} = \tfrac{5}{15}. Two columns are \tfrac{2}{5}, and each column holds 3 cells, so \tfrac{2}{5} = \tfrac{6}{15}.
The opening and middle are \tfrac{11}{15} of the routine. That leaves \tfrac{4}{15} for the last section.
Practice time in twelfths
Lanre stretches for \tfrac{3}{4} hour and then rests for \tfrac{1}{12} hour. How long is that altogether, in simplest form?
SolutionDivide the larger denominator by the smaller: 12 \div 4 = 3, a whole number. So 12 is a multiple of 4, twelfths can be the shared piece, and only \tfrac{3}{4} has to change. Multiply its top and bottom by 3, which cuts each quarter hour into 3 twelfths:
Both 10 and 12 can be divided by 2, so the answer is not yet in simplest form.
Now 5 and 6 share no factor except 1, so \tfrac{5}{6} hour is the simplest form. As a check, \tfrac{5}{6} of 60 minutes is 50 minutes, and 45 minutes plus 5 minutes is 50 minutes.
Spotting a less obvious multiple
Aiyana’s banner is \tfrac{3}{8} purple and \tfrac{5}{24} gold. What fraction is purple or gold?
SolutionIs 24 a multiple of 8? Divide: 24 \div 8 = 3, so yes, and 24 can be the shared denominator. Multiply the top and bottom of \tfrac{3}{8} by 3:
Both 14 and 24 are even, so divide both by 2:
7 has no factor but 1 and itself, and 7 does not divide 12, so \tfrac{7}{12} is in simplest form. The banner is \tfrac{7}{12} purple or gold.
Neither denominator fits the other
Dohyun practices turns for \tfrac{3}{5} hour and jumps for \tfrac{1}{3} hour. How long does he practice?
Solution5 \div 3 and 3 \div 5 are not whole numbers, so neither denominator is a multiple of the other, and both fractions must change. 3 and 5 share no factor except 1, so the least common denominator is the product, 3 \times 5 = 15. Multiply each fraction, top and bottom, by the other denominator:
14 and 15 share no factor except 1, so \tfrac{14}{15} is in simplest form. Dohyun practices \tfrac{14}{15} of an hour, which is 56 minutes, just under an hour.
The product or the least common denominator
Aiyana spends \tfrac{1}{6} hour putting on her shoes and warming up, and \tfrac{5}{8} hour in the center of the room. Find the total twice, once with the product of the denominators and once with the least common denominator.
SolutionWith the product, 6 \times 8 = 48. Multiply \tfrac{1}{6} by \tfrac{8}{8} and \tfrac{5}{8} by \tfrac{6}{6}:
The last step divides the top and bottom by 2.
With the least common denominator, list multiples of 8: 8, 16, 24. 24 is the first that 6 divides, since 6 \times 4 = 24. Multiply \tfrac{1}{6} by \tfrac{4}{4} and \tfrac{5}{8} by \tfrac{3}{3}:
Both routes give \tfrac{19}{24} hour. The least common denominator gave smaller numbers and an answer already in simplest form. The product needed one more step, simplifying, but it reached the same amount.
Cutting a banner
Lanre has a strip of banner paper \tfrac{9}{10} of a yard long. He cuts off \tfrac{2}{3} of a yard for a banner. How much paper is left?
SolutionTaking away is subtraction: \tfrac{9}{10} - \tfrac{2}{3}. Neither 10 nor 3 divides the other, and they share no factor except 1, so use 10 \times 3 = 30.
7 does not divide 30, so \tfrac{7}{30} is in simplest form. Lanre has \tfrac{7}{30} of a yard left.
Check by adding back: \tfrac{7}{30} + \tfrac{20}{30} = \tfrac{27}{30}, which is the \tfrac{9}{10} of a yard he started with.
Three days of practice
Aiyana practices \tfrac{3}{4} hour on Monday, \tfrac{2}{3} hour on Wednesday and \tfrac{5}{6} hour on Friday. How many hours does she practice in all? Write the answer as a mixed number.
SolutionFind one denominator that 4, 3 and 6 all divide. Multiples of the largest, 6, are 6 and 12. 4 does not divide 6, but 4, 3 and 6 all divide 12. So rename each fraction in twelfths:
The top is bigger than the bottom, so this is more than 1 hour. Divide: 27 \div 12 = 2 remainder 3, so \tfrac{27}{12} = 2\tfrac{3}{12}. The fraction part simplifies, since 3 and 12 can both be divided by 3: \tfrac{3}{12} = \tfrac{1}{4}.
Aiyana practices 2\tfrac{1}{4} hours in all. As a check, each day is less than 1 hour, so the total must be less than 3 hours, and each day is more than half an hour, so the total must be more than 1\tfrac{1}{2} hours. 2\tfrac{1}{4} hours fits.
Boundaries
- The same whole. Adding \tfrac{1}{2} and \tfrac{3}{10} gives \tfrac{4}{5} only when both are fractions of the same whole, such as one hour or one banner. Half of a small banner and three tenths of a large one are not \tfrac{4}{5} of either.
- Only the numerators add. The denominator names the size of the pieces. Once the pieces match, the count changes and the size stays. Adding the denominators would change the size of the pieces, which gives a wrong amount.
- No zero denominators. A denominator says how many equal parts the whole is cut into, so it is never 0. Every fraction in this lesson has a denominator of at least 2.
- Larger minus smaller. In this lesson every difference takes a smaller fraction from a larger one. The other order gives a number below zero, which needs negative numbers (Operations with rational numbers).
- Proper fractions only. Every fraction added or subtracted here is less than 1 (once, in Exercise 23, a part is taken from the whole, 1). Adding or subtracting mixed numbers, such as 2\tfrac{1}{3} + 1\tfrac{3}{4}, is the work of Adding mixed numbers and Subtracting mixed numbers.
- Adding and subtracting only. A common denominator is needed to add or subtract. It is not needed to multiply fractions (Multiplying fractions), where tops multiply and bottoms multiply.
Where this goes next
Mixed numbers come next. To find 1\tfrac{2}{3} + 2\tfrac{1}{4}, add the whole numbers and add the fraction parts, and the fraction parts are exactly the sums of this lesson (Adding mixed numbers). Subtracting mixed numbers sometimes needs a whole number broken into pieces first (Subtracting mixed numbers). Longer story problems, where you must read the situation to decide whether amounts are joined or taken away, are in Word problems that add or subtract fractions.
Later, the same renaming works with negative fractions (Operations with rational numbers), and later still with fractions that have letters in them. The idea never changes: rename to one piece size, then count.
Exercises
Part 1: strips and area models
Draw a picture for each sum, then write the sum as a fraction.
- Use fraction strips to find \tfrac{1}{2} + \tfrac{3}{8}.
- Use an area model to find \tfrac{1}{2} + \tfrac{1}{5}.
- Use an area model to find \tfrac{2}{3} + \tfrac{1}{5}.
Part 2: one denominator a multiple of the other
Add. Write each answer in simplest form.
- \tfrac{1}{3} + \tfrac{5}{9}
- \tfrac{2}{5} + \tfrac{1}{10}
- \tfrac{1}{4} + \tfrac{5}{12}
- \tfrac{3}{7} + \tfrac{5}{14}
- \tfrac{1}{6} + \tfrac{7}{18}
- Dohyun spends \tfrac{1}{6} hour warming up and \tfrac{2}{3} hour learning a new dance. How long is that altogether?
Part 3: neither denominator a multiple of the other
Add. Write each answer in simplest form.
- \tfrac{3}{4} + \tfrac{1}{5}
- \tfrac{2}{7} + \tfrac{1}{3}
- \tfrac{2}{9} + \tfrac{1}{6}
- \tfrac{3}{10} + \tfrac{2}{15}
- \tfrac{5}{12} + \tfrac{1}{8}
- Aiyana covers \tfrac{1}{6} of a banner with stars and \tfrac{3}{10} of it with stripes. What fraction of the banner is covered?
- Find \tfrac{3}{10} + \tfrac{1}{4} twice: once with the product of the denominators and once with the least common denominator. Show that the answers agree.
Part 4: subtracting, sums over one, three fractions
Write each answer in simplest form. Write a sum greater than 1 as a mixed number.
- \tfrac{3}{4} - \tfrac{1}{3}
- \tfrac{7}{10} - \tfrac{1}{2}
- \tfrac{5}{6} - \tfrac{2}{9}
- \tfrac{2}{3} + \tfrac{3}{5}
- \tfrac{7}{8} + \tfrac{5}{12}
- \tfrac{1}{2} + \tfrac{2}{3} + \tfrac{1}{6}
- Lanre learned \tfrac{3}{8} of his routine on Monday and \tfrac{1}{3} of it on Wednesday. What fraction of the routine does he still have to learn?
Reasoning
- Explain why, when one denominator is a multiple of the other, the larger denominator is always the least common denominator.
- A proper fraction is less than 1. Explain why the sum of two proper fractions is always less than 2, and why the difference of two proper fractions (larger minus smaller) is always less than 1.
Answers
- \tfrac{7}{8}. Cut each half of the strip into 4 eighths, so \tfrac{1}{2} = \tfrac{4}{8}, and \tfrac{4}{8} + \tfrac{3}{8} = \tfrac{7}{8}.
- \tfrac{7}{10}. A square with 2 rows and 5 columns has 10 cells. One row is 5 cells and one column is 2 cells, so \tfrac{5}{10} + \tfrac{2}{10} = \tfrac{7}{10}.
- \tfrac{13}{15}. A square with 3 rows and 5 columns has 15 cells. Two rows are 10 cells and one column is 3 cells, so \tfrac{10}{15} + \tfrac{3}{15} = \tfrac{13}{15}.
- \tfrac{8}{9}. 9 \div 3 = 3, so \tfrac{1}{3} = \tfrac{3}{9}, and \tfrac{3}{9} + \tfrac{5}{9} = \tfrac{8}{9}.
- \tfrac{1}{2}. \tfrac{2}{5} = \tfrac{4}{10}, so the sum is \tfrac{5}{10}, and dividing top and bottom by 5 gives \tfrac{1}{2}.
- \tfrac{2}{3}. \tfrac{1}{4} = \tfrac{3}{12}, so the sum is \tfrac{8}{12}, and dividing top and bottom by 4 gives \tfrac{2}{3}.
- \tfrac{11}{14}. \tfrac{3}{7} = \tfrac{6}{14}, and \tfrac{6}{14} + \tfrac{5}{14} = \tfrac{11}{14}.
- \tfrac{5}{9}. \tfrac{1}{6} = \tfrac{3}{18}, so the sum is \tfrac{10}{18}, and dividing top and bottom by 2 gives \tfrac{5}{9}.
- \tfrac{5}{6} hour. \tfrac{2}{3} = \tfrac{4}{6}, and \tfrac{1}{6} + \tfrac{4}{6} = \tfrac{5}{6}.
- \tfrac{19}{20}. With denominator 20: \tfrac{15}{20} + \tfrac{4}{20} = \tfrac{19}{20}.
- \tfrac{13}{21}. With denominator 21: \tfrac{6}{21} + \tfrac{7}{21} = \tfrac{13}{21}.
- \tfrac{7}{18}. The least common denominator is 18: \tfrac{4}{18} + \tfrac{3}{18} = \tfrac{7}{18}.
- \tfrac{13}{30}. The least common denominator is 30: \tfrac{9}{30} + \tfrac{4}{30} = \tfrac{13}{30}.
- \tfrac{13}{24}. The least common denominator is 24: \tfrac{10}{24} + \tfrac{3}{24} = \tfrac{13}{24}.
- \tfrac{7}{15} of the banner. With denominator 30: \tfrac{5}{30} + \tfrac{9}{30} = \tfrac{14}{30}, and dividing top and bottom by 2 gives \tfrac{7}{15}.
- \tfrac{11}{20} both ways. Product 40: \tfrac{12}{40} + \tfrac{10}{40} = \tfrac{22}{40}, which simplifies to \tfrac{11}{20}. Least common denominator 20: \tfrac{6}{20} + \tfrac{5}{20} = \tfrac{11}{20}.
- \tfrac{5}{12}. With denominator 12: \tfrac{9}{12} - \tfrac{4}{12} = \tfrac{5}{12}.
- \tfrac{1}{5}. \tfrac{1}{2} = \tfrac{5}{10}, so the difference is \tfrac{2}{10}, and dividing top and bottom by 2 gives \tfrac{1}{5}.
- \tfrac{11}{18}. The least common denominator is 18: \tfrac{15}{18} - \tfrac{4}{18} = \tfrac{11}{18}.
- 1\tfrac{4}{15}. With denominator 15: \tfrac{10}{15} + \tfrac{9}{15} = \tfrac{19}{15}, and 19 \div 15 = 1 remainder 4.
- 1\tfrac{7}{24}. The least common denominator is 24: \tfrac{21}{24} + \tfrac{10}{24} = \tfrac{31}{24}, and 31 \div 24 = 1 remainder 7.
- 1\tfrac{1}{3}. With denominator 6: \tfrac{3}{6} + \tfrac{4}{6} + \tfrac{1}{6} = \tfrac{8}{6}, which is 1\tfrac{2}{6}, and \tfrac{2}{6} = \tfrac{1}{3}.
- \tfrac{7}{24} of the routine. He has learned \tfrac{9}{24} + \tfrac{8}{24} = \tfrac{17}{24}. The whole routine is \tfrac{24}{24}, so \tfrac{24}{24} - \tfrac{17}{24} = \tfrac{7}{24} is left.
- Say the denominators are 3 and 12. The larger, 12, is a multiple of itself, and it is a multiple of 3 because 3 \times 4 = 12. So it is a common denominator. No common denominator can be smaller, because a common denominator must be a multiple of 12, and the smallest multiple of 12 that is not 0 is 12 itself. The same reasoning works for any pair where the larger denominator is a multiple of the smaller one.
- Each fraction is less than 1, so two of them together are less than 1 + 1 = 2. For the difference, the larger fraction is less than 1, and taking away the smaller one (which is not below 0) can only make it smaller, so the difference is less than 1 too. For example, \tfrac{9}{10} + \tfrac{7}{8} is close to 2 but below it, and \tfrac{9}{10} - \tfrac{1}{8} is close to 1 but below it.