Algebra 2 · Chapter 8 · Lesson 8.10 · Printable PDF

Solving Logarithmic Equations Worksheet with Answer Key

5 problems on solving logarithmic equations: writing the domain first, rejecting extraneous candidates, domains before and after a law of logs, finding a constant k, and finding the step where Jasmine's solution goes wrong. 2 pages, with a worked answer key.

5 problems2 pagesanswer key
Printable Solving logarithmic equations worksheet with answer key - Algebra 2 (Page 1 PDF preview)
Page 1 of 2

Get this sheet

This sheetWorksheet and answer key, yours to keep.
$5
Buy
SubscriptionOpen any sheet in any course, up to 40 a month, keys included. Or $40 month to month.
$25/mo, billed yearly
Subscribe
Full Course Set490+ Algebra 2 PDF files, no limit, yours to keep.
$400once
Buy

Try one first: a free Chapter 1 worksheet (PDF, no sign-in).

The full Algebra 2 courseEvery lesson in teaching order, with over 490 printables.See the course ›

What's on the worksheet

  1. Solve each equation with exact answers, writing the domain and rejecting any candidate.
    \log_7(x + 1) + \log_7(x - 5) = 1\ln(x + 2) - \ln(x - 1) = \ln 4\log_3 x + \log_3(x + 2) = \log_3(4x + 15)\log_5(x - 4) + \log_5(x + 4) = 2
  2. For each pair, give the domain of each expression and see what a law of logs changes.
    \log x + \log(x - 3) and \log\big(x(x - 3)\big)\ln(x + 2) - \ln(x - 1) and \ln \dfrac{x + 2}{x - 1}2\log_2 x and \log_2\left(x^2\right)\log_3(x - 4) + \log_3(6 - x) and \log_3\big((x - 4)(6 - x)\big)
  3. Find k so that x equals 3 solves the equation, then solve with that k.
  4. Find the step where Jasmine's solution of a log equation goes wrong.
  5. Explain how an equation of two added logs is solved by condensing and why a check is needed.

Teach it first

The free lesson teaches it with worked examples and practice problems.

Solving logarithmic equations: the lesson ›