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- Decide whether each series converges or diverges.\sum_{n=1}^{\infty} \dfrac{n^2 + 1}{\sqrt{n^4 + 3}}\sum_{n=1}^{\infty} \dfrac{n^n}{3^{n^2}}\sum_{n=1}^{\infty} \dfrac{n^3\, 4^n}{(n+1)!}\sum_{n=1}^{\infty} \dfrac{1}{n\left(1 + (\ln n)^2\right)}
- Classify each series as absolutely convergent, conditionally convergent, or divergent.\sum_{n=1}^{\infty} (-1)^n \dfrac{n^3}{2^n}\sum_{n=1}^{\infty} (-1)^{n+1} \left(\sqrt{n+1} - \sqrt{n}\right)\sum_{n=1}^{\infty} (-1)^n \dfrac{\sin^2 n}{n^2}\sum_{n=1}^{\infty} (-1)^n \dfrac{3^n}{3^n + n^3}
- Let S be the sum of the series below, if it exists.
- Consider the series below.
- Consider the series below.
- For each description, give a series that fits it and show that it does, or explain why no series can fit it.
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Choosing a convergence test: the lesson ›More Chapter 5 worksheets: Sequences and series: convergence
- 5.1Convergence of sequences
- 5.2Infinite series and partial sums
- 5.3The geometric series test
- 5.4The nth term test for divergence
- 5.5The integral test and p series
- 5.6The direct and limit comparison tests
- 5.7Alternating series and their error bound
- 5.8Absolute and conditional convergence
- 5.9The ratio and root tests
- 5.10Choosing a convergence test