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- Write each term as Cn^p for a constant C, name p, and decide whether the series converges by the p-series test.\displaystyle\sum_{n=1}^{\infty} \dfrac{1}{\sqrt{n^3}}\displaystyle\sum_{n=1}^{\infty} n^{-2/3}\displaystyle\sum_{n=1}^{\infty} \dfrac{n^2}{\sqrt[3]{n^7}}\displaystyle\sum_{n=1}^{\infty} \dfrac{4}{n\sqrt[4]{n}}\displaystyle\sum_{n=1}^{\infty} \dfrac{\sqrt[5]{n^2}}{n\sqrt{n}}
- Use the integral test.\displaystyle\sum_{n=1}^{\infty} \dfrac{1}{n(1 + \ln n)}\displaystyle\sum_{n=1}^{\infty} \dfrac{\arctan n}{1 + n^2}
- Consider the series below, and let $f
- Let S_N = _n=1^N 1[4]n.
- The series _n=1^∞ 1n² + 1 has a sum S known to be about 1.076674.
- Consider the series below, where p is a real number.
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The integral test and p series: the lesson ›More Chapter 5 worksheets: Sequences and series: convergence
- 5.1Convergence of sequences
- 5.2Infinite series and partial sums
- 5.3The geometric series test
- 5.4The nth term test for divergence
- 5.5The integral test and p series
- 5.6The direct and limit comparison tests
- 5.7Alternating series and their error bound
- 5.8Absolute and conditional convergence
- 5.9The ratio and root tests
- 5.10Choosing a convergence test