Calculus 2 · Chapter 5 · Lesson 5.6 · Printable PDF

The Direct and Limit Comparison Tests Worksheet with Answer Key

6 problems on the direct and limit comparison tests. 2 pages, with a worked answer key.

6 problems2 pagesanswer key
Printable The direct and limit comparison tests worksheet with answer key - Calculus 2 (Page 1 PDF preview)
Page 1 of 2

Get this sheet

This sheetWorksheet and answer key, yours to keep.
$5
Buy
SubscriptionOpen any sheet in any course, up to 40 a month, keys included. Or $40 month to month.
$25/mo, billed yearly
Subscribe
Full Course Set160+ Calculus 2 PDF files, no limit, yours to keep.
$400once
Buy

Try one first: a free Chapter 1 worksheet (PDF, no sign-in).

The full Calculus 2 courseEvery lesson in teaching order, with over 160 printables.See the course ›

What's on the worksheet

  1. Decide whether each series converges or diverges by the direct comparison test.
    \displaystyle\sum_{n=1}^{\infty} \dfrac{1}{n^2 + 7n}\displaystyle\sum_{n=1}^{\infty} \dfrac{1}{n\,3^n}\displaystyle\sum_{n=2}^{\infty} \dfrac{\ln n}{n}\displaystyle\sum_{n=1}^{\infty} \dfrac{n!}{n^n}
  2. Decide whether each series converges or diverges by the limit comparison test.
    \displaystyle\sum_{n=1}^{\infty} \dfrac{3n^2 - 1}{n^4 + 5n}\displaystyle\sum_{n=1}^{\infty} \dfrac{\sqrt{n} + 1}{2n - 1}\displaystyle\sum_{n=1}^{\infty} \left(e^{1/n} - 1\right)\displaystyle\sum_{n=1}^{\infty} \dfrac{2n + \ln n}{n^3 + 1}
  3. Decide whether each series converges or diverges.
    \displaystyle\sum_{n=2}^{\infty} \dfrac{1}{(\ln n)^2}\displaystyle\sum_{n=1}^{\infty} \dfrac{\sqrt{n}}{e^{\sqrt{n}}}\displaystyle\sum_{n=1}^{\infty} \left(\sqrt{n^2 + 1} - n\right)
  4. Each argument below has a flaw.
  5. Let S = _n=1^∞ 1n³ + 1, and let S_N be its Nth partial sum.
  6. Suppose a_n > 0 for every n and _n=1^∞ a_n converges.

Teach it first

The free lesson teaches it with worked examples and practice problems.

The direct and limit comparison tests: the lesson ›